Question

我想在http请求中获取Gatling

的随机网址

我的场景定义如下：

import io.gatling.core.Predef._
import io.gatling.http.Predef._
import scala.concurrent.duration._
import scala.util.Random

class testSimulation extends Simulation {

  val httpConf = http.baseURL("OURURL")


  val scn = scenario("View HomePages")
                .exec(
                        http("Home page")
                                .get("/" + new Random().nextInt())
                              .resources(
                                      http("genericons.css").get("/wp-content/themes/twentyfifteen/genericons/generi$
                                      http("style.css").get("/wp-content/themes/twentyfifteen/style.css?ver=4.2.3"),
                                      http("jquery.js").get("/wp-includes/js/jquery/jquery.js?ver=1.11.2"),
                                      http("jquery-migrate.min.js").get("/wp-includes/js/jquery/jquery-migrate.min.j$
                                      http("skip-link-focus-fix.js").get("/wp-content/themes/twentyfifteen/js/skip-l$
                                      http("functions.js").get("/wp-content/themes/twentyfifteen/js/functions.js?ver$
                                      http("wp-emoji-release.min.js").get("/wp-includes/js/wp-emoji-release.min.js?v$
                                      http("wp-emoji-release.min.js").get("/wp-includes/js/wp-emoji-release.min.js?v$
                                      http("skip-link-focus-fix.js").get("/wp-content/themes/twentyfifteen/js/skip-l$
                                      http("functions.js").get("/wp-content/themes/twentyfifteen/js/functions.js?ver$
                              )
                )

  setUp(
      scn.inject
      (
      rampUsersPerSec(1) to(300) during(60 seconds),
      constantUsersPerSec(300) during(600 seconds)
      )
      .protocols(httpConf)
      )
}

我只生成一个随机数而不是每个请求一个。你知道怎么解决吗？谢谢！

Answer 1

您传递了一个值，因此当构建Simulation时，new Random().nextInt只会被调用一次。

你必须传递一个Expression，即一个函数。只有这样才会每次都进行评估。

.get(session => "/" + new Random().nextInt())

如何在http请求中获取Gatling的随机URL？

1 个答案: