Question

是否有一种简单的方法来分割保持分隔符的字符串？而不是：

let texte = "Ten. Million. Questions. Let's celebrate all we've done together.";
let v: Vec<&str> = texte.split(|c: char| !(c.is_alphanumeric() || c == '\'')).filter(|s| !s.is_empty()).collect();

以["Ten", "Million", "Questions", "Let's", "celebrate", "all", "we've", "done", "together"]生成。

我想要一些能给我的东西：

["Ten", ".", " ", "Million", ".", " ", "Questions", ".", " ", "Let's", " ", "celebrate", " ", "all", " ", "we've", " ", "done", " ", "together", "."]。

我正在尝试这种代码（它假设字符串以字母开头，以＆＃39;非＆＃39;字母结尾）：

let texte = "Ten. Million. Questions. Let's celebrate all we've done together.  ";
let v1: Vec<&str> = texte.split(|c: char| !(c.is_alphanumeric() || c == '\'')).filter(|s| !s.is_empty()).collect();
let v2: Vec<&str> = texte.split(|c: char| c.is_alphanumeric() || c == '\'').filter(|s| !s.is_empty()).collect();
let mut w: Vec<&str> = Vec::new();

let mut j = 0;
for i in v2 {
    w.push(v1[j]);
    w.push(i);
    j = j+1;
}

它给了我几乎我之前写的结果，但它很好：

["Ten", ". ", "Million", ". ", "Questions", ". ", "Let's", " ", "celebrate", " ", "all", " ", "we've", " ", "done", " ", "together", "."]

但是有更好的方法来编码吗？因为我试图在v2上进行枚举，但它没有工作，并且在for循环中使用j看起来很粗糙。

Answer 1

使用str::match_indices：

let text = "Ten. Million. Questions. Let's celebrate all we've done together.";

let mut result = Vec::new();
let mut last = 0;
for (index, matched) in text.match_indices(|c: char| !(c.is_alphanumeric() || c == '\'')) {
    if last != index {
        result.push(&text[last..index]);
    }
    result.push(matched);
    last = index + matched.len();
}
if last < text.len() {
    result.push(&text[last..]);
}

println!("{:?}", result);

打印：

["Ten", ".", " ", "Million", ".", " ", "Questions", ".", " ", "Let\'s", " ", "celebrate", " ", "all", " ", "we\'ve", " ", "done", " ", "together", "."]

Answer 2

我无法在标准库中找到任何内容，因此I wrote my own：

此版本使用不稳定模式API，因为它更灵活，但上面的链接有我为特定稳定用例硬编码的后备。

#![feature(pattern)]

use std::str::pattern::{Pattern, Searcher};

#[derive(Copy, Clone, Debug, PartialEq)]
pub enum SplitType<'a> {
    Match(&'a str),
    Delimiter(&'a str),
}

pub struct SplitKeepingDelimiter<'p, P>
where
    P: Pattern<'p>,
{
    searcher: P::Searcher,
    start: usize,
    saved: Option<usize>,
}

impl<'p, P> Iterator for SplitKeepingDelimiter<'p, P>
where
    P: Pattern<'p>,
{
    type Item = SplitType<'p>;

    fn next(&mut self) -> Option<Self::Item> {
        if self.start == self.searcher.haystack().len() {
            return None;
        }

        if let Some(end_of_match) = self.saved.take() {
            let s = &self.searcher.haystack()[self.start..end_of_match];
            self.start = end_of_match;
            return Some(SplitType::Delimiter(s));
        }

        match self.searcher.next_match() {
            Some((start, end)) => {
                if self.start == start {
                    let s = &self.searcher.haystack()[start..end];
                    self.start = end;
                    Some(SplitType::Delimiter(s))
                } else {
                    let s = &self.searcher.haystack()[self.start..start];
                    self.start = start;
                    self.saved = Some(end);
                    Some(SplitType::Match(s))
                }
            }
            None => {
                let s = &self.searcher.haystack()[self.start..];
                self.start = self.searcher.haystack().len();
                Some(SplitType::Match(s))
            }
        }
    }
}

pub trait SplitKeepingDelimiterExt: ::std::ops::Index<::std::ops::RangeFull, Output = str> {
    fn split_keeping_delimiter<P>(&self, pattern: P) -> SplitKeepingDelimiter<P>
    where
        P: for<'a> Pattern<'a>,
    {
        SplitKeepingDelimiter {
            searcher: pattern.into_searcher(&self[..]),
            start: 0,
            saved: None,
        }
    }
}

impl SplitKeepingDelimiterExt for str {}

#[cfg(test)]
mod test {
    use super::SplitKeepingDelimiterExt;

    #[test]
    fn split_with_delimiter() {
        use super::SplitType::*;
        let delims = &[',', ';'][..];
        let items: Vec<_> = "alpha,beta;gamma".split_keeping_delimiter(delims).collect();
        assert_eq!(
            &items,
            &[
                Match("alpha"),
                Delimiter(","),
                Match("beta"),
                Delimiter(";"),
                Match("gamma")
            ]
        );
    }

    #[test]
    fn split_with_delimiter_allows_consecutive_delimiters() {
        use super::SplitType::*;
        let delims = &[',', ';'][..];
        let items: Vec<_> = ",;".split_keeping_delimiter(delims).collect();
        assert_eq!(&items, &[Delimiter(","), Delimiter(";")]);
    }
}

您需要注意的是，我需要跟踪某些内容是否是分隔符之一，但如果您不需要，这应该很容易适应。

Answer 3

不稳定函数str::split_inclusive返回一个迭代器，将分隔符保留为匹配字符串的一部分，在某些情况下可能有用：

#![feature(split_inclusive)]

#[test]
fn split_with_delimiter() {
    let items: Vec<_> = "alpha,beta;gamma"
        .split_inclusive(&[',', ';'][..])
        .collect();
    assert_eq!(&items, &["alpha,", "beta;", "gamma"]);
}

#[test]
fn split_with_delimiter_allows_consecutive_delimiters() {
    let items: Vec<_> = ",;".split_inclusive(&[',', ';'][..]).collect();
    assert_eq!(&items, &[",", ";"]);
}

拆分保持分隔符的字符串

3 个答案: