我有一个应用程序,它在服务中使用持久性通知并在后台运行。当此服务正在运行时,我需要能够在单击通知时调用方法/执行某些操作。但是,我不确定如何实现这一点。 我已阅读了许多类似的问题/答案,但没有一个人能够清楚地或适当地回答我的目的。 This所以问题接近我想要实现的目标,但所选答案是很难理解。
我的服务/通知是在我的BackgroundService类的onCreate()方法中启动的......
Notification notification = new Notification();
startForeground(1, notification);
registerReceiver(receiver, filter);
此服务从我的主要活动的按钮点击启动:
final Intent service = new Intent(Main.this, BackgroundService.class);
bStart.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
if((counter % 2) == 0){
bStart.setText("STOP");
startService(service);
}else {
bStart.setText("BEGIN");
stopService(service);
}
counter++;
}
任何建议表示赞赏
答案 0 :(得分:1)
你必须使用BroadcastReceiver
。看看下面的代码。把它放在Service
private MyBroadcastReceiver mBroadcastReceiver;
@Override
onCreate() {
super.onCreate();
mBroadcastReceiver = new MyBroadcastReceiver();
IntentFilter intentFilter = new IntentFilter();
intentFilter.addCategory(Intent.CATEGORY_DEFAULT);
// set the custom action
intentFilter.addAction("do_something");
registerReceiver(mBroadcastReceiver, intentFilter);
}
// While making notification
Intent i = new Intent("do_something");
PendingIntent pendingIntent = PendingIntent.getBroadcast(this, 0, i, 0);
notification.contentIntent = pendingIntent;
public class MyBroadcastReceiver extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent) {
String action = intent.getAction();
switch(action) {
case "do_something":
doSomething();
break;
}
}
}
public void doSomething() {
//Whatever you wanna do on notification click
}
这样,点击doSomething()
时,系统会调用Notification
方法。