我试图通过ajax将数据提交到数据库。提交文章页面没有ajax工作正常。我已添加console.log()只是为了查看是否有任何问题，但我收到了此错误：
POST http://localhost/laravel-5/public/articles/create 500（内部服务器错误）
我的代码出了什么问题？是javascript还是控制器？
编辑：我在laravel.log
exception＆＃39; Illuminate \ Session \ TokenMismatchException＆＃39;在C：\ xampp \ htdocs \ laravel-5 \ vendor \ laravel \ framework \ src \ Illuminate \ Foundation \ Http \ Middleware \ VerifyCsrfToken.php：53
路线
Route::resource('articles', 'ArticlesController');
控制器
public function store(Requests\ArticleRequest $request)
{
$article = new Article($request->all());
Auth::user()->articles()->save($article);
$response = array(
'status' => 'success',
'msg' => 'Article has been posted.',
);
return \Response::json($response);
}
的jQuery
$(document).ready(function() {
$('#frm').on('submit', function (e) {
e.preventDefault();
var title = $('#title').val();
var body = $('#body').val();
var published_at = $('#published_at').val();
$.ajax({
type: "POST",
url: 'http://localhost/laravel-5/public/articles/create',
dataType: 'JSON',
data: {title: title, body: body, published_at: published_at},
success: function( data ) {
$("#ajaxResponse").append(data.msg);
console.log(data);
}
});
});
查看
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/css/bootstrap.min.css">
<h1>Write a New Article</h1>
<hr>
{!! Form::open(['url' => 'articles', 'id' => 'frm']) !!}
<p>
{!! Form::label('title', 'Title:') !!}
{!! Form::text('title') !!}
</p>
<p>
{!! Form::label('body', 'Body:') !!}
{!! Form::textarea('body') !!}
</p>
<p>
{!! Form::label('published_at', 'Date:') !!}
{!! Form::input('date', 'published_at', date('Y-m-d'), ['class' => 'form-control']) !!}
</p>
<p>
{!! Form::submit('Submit Article', ['id' => 'submit']) !!}
</p>
{!! Form::close() !!}
<h3 id="ajaxResponse"></h3>
@if($errors->any())
<ul>
@foreach($errors->all() as $error)
<li>{{ $error }}</li>
@endforeach
</ul>
@endif
<script src="//code.jquery.com/jquery-1.11.0.min.js"></script>
<script src="{{ URL::asset('assets/js/ArticleCreate.js') }}"></script>
}）;
答案 0 :(得分：13)
当您通过POST向资源控制器发出请求时，它会自动调用存储方法：
Verb Path Action Route Name
----------------------------------
POST /articles store articles.store
所以，你只需要将ajax url更改为：
$.ajax({
type: "POST",
url: 'http://localhost/laravel-5/public/articles',
当您需要发送会话令牌时，您可以添加一个全局元标记，例如这是您的网站：
<meta name="csrf-token" content="{{ csrf_token() }}">
然后，只需通过ajax的标题添加令牌：
$.ajaxSetup({
headers: {
'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')
}
});
如果您使用的是Form::open()函数（LaravelCollective），则会添加一个隐藏的输入，并将该标记作为值_token的值。因此，您可以删除元标记并编辑您的ajax标题，如下所示：
$.ajaxSetup({
headers: {
'X-CSRF-TOKEN': $('[name="_token"]').val()
}
});
答案 1 :(得分：2)
这就是我在C：\ xampp \ htdocs \ laravel-5 \ vendor \ laravel \ framework \ src \ Illuminate \ Foundation \ Htt p \ Middleware \ VerifyCsrfToken.php中得到异常'Illuminate \ Session \ TokenMismatchException'：53
你正在使用Laravel的CSRF保护。
http://laravel.com/docs/5.1/routing#csrf-protection
您需要传递隐藏的_token字段的值。这可以通过在应用程序的JS中执行此操作，在所有jQuery启动的AJAX请求上自动完成：
$.ajaxSetup({
headers: {
'X-CSRF-TOKEN': $('input[name="_token"]').value()
}
});
或者，您可以在每个AJAX调用中手动获取并传递_token隐藏字段的值。
答案 2 :(得分：0)
我喜欢分享此代码以帮助某人需要ajax帖子并使用laravel
<<<<<<<<
POST
<<<<
<<look after @extends<<
<<look beforeSend: function (xhr) <<
<<look use Illuminate\Http\Request in Routes<<
<<<------<<views\login\login.blade.php<<<<-----------<<<
@extends('cuerpito.web')
<meta name="csrf_token" content="{{ csrf_token() }}" />
@section('content')
<form action="#" id="logForm" method="post" class="form-horizontal">
<div class="form-group">
<div class="col-xs-12">
<div class="input-group">
<input type="email" id="email" name="email" class="form-control input-lg" placeholder="Ingresa tu Email." autocomplete="off">
</div>
</div>
</div>
<div class="form-group">
<div class="col-xs-12">
<div class="input-group">
<input type="password" id="password" name="password" class="form-control input-lg" placeholder="Ingresa tu Contraseña." autocomplete="off">
</div>
</div>
</div>
<div class="form-group formSubmit">
<div class="col-xs-12">
<div class="input-group">
<button type="submit" name="feedbackSubmit" id="feedbackSubmit" class="btn btn-success btn-lg" style="display: block; margin-top: 10px;">Ingresar</button>
</div>
</div>
</div>
</form>
<script type="text/javascript">
$(document).ready(function () {
$("#feedbackSubmit").click(function () {
$.ajax({
url: '{{URL::route('login4')}}',
type: "post",
beforeSend: function (xhr) {
var token = $('meta[name="csrf_token"]').attr('content');
if (token) {
return xhr.setRequestHeader('X-CSRF-TOKEN', token);
}
},
data: $("#logForm").serialize(),
success: function (data)
{
if (data) {
alert(data);
console.log(data);
} else {
console.log(data);
}//else
}//success
});//ajax
return false;
});//feedbacksubmit
});//document ready
</script>
-------------0----------------------
-------------0----------------------
<<<----<<app\Http\routes.php<<<<-----------<<<
<?php
use Illuminate\Http\Request;
Route::post('login4', function()
{
return 'Success! POST Ajax in laravel 5';
})->name('login4');
------------------0----------------------
------------------0----------------------
<<<<
Get
<<look after @extends<<
<<look beforeSend: function (xhr) <<
<<look use Illuminate\Http\Request in Routes<<
<<<------<<views\login\login.blade.php<<<<-----------<<<
@extends('cuerpito.web')
<meta name="csrf_token" content="{{ csrf_token() }}" />
@section('content')
<form action="#" id="logForm" method="post" class="form-horizontal">
<div class="form-group">
<div class="col-xs-12">
<div class="input-group">
<input type="email" id="email" name="email" class="form-control input-lg" placeholder="Ingresa tu Email." autocomplete="off">
</div>
</div>
</div>
<div class="form-group">
<div class="col-xs-12">
<div class="input-group">
<input type="password" id="password" name="password" class="form-control input-lg" placeholder="Ingresa tu Contraseña." autocomplete="off">
</div>
</div>
</div>
<div class="form-group formSubmit">
<div class="col-xs-12">
<div class="input-group">
<button type="submit" name="feedbackSubmit" id="feedbackSubmit" class="btn btn-success btn-lg" style="display: block; margin-top: 10px;">Ingresar</button>
</div>
</div>
</div>
</form>
<script type="text/javascript">
$(document).ready(function () {
$("#feedbackSubmit").click(function () {
$.ajax({
url: '{{URL::route('login2')}}',
type: "get",
beforeSend: function (xhr) {
var token = $('meta[name="csrf_token"]').attr('content');
if (token) {
return xhr.setRequestHeader('X-CSRF-TOKEN', token);
}
},
data: $("#logForm").serialize(),
success: function (data)
{
if (data) {
obj = JSON.stringify(data, null, " ");
var datito = JSON.parse(obj);
console.log(datito.response);
alert(datito.response);
} else {
console.log(data);
}//else
}//success
});//ajax
return false;
});//feedbacksubmit
});//document ready
</script>
-------------0----------------------
-------------0----------------------
<<<----<<app\Http\routes.php<<<<-----------<<<
<?php
use Illuminate\Http\Request;
Route::get('login2', 'WebController@login2')->name('login2');
-------------0----------------------
-------------0----------------------
<<<----<<Http\Controllers\WebController.php<<<<-----------<<<
public function login2(Request $datos) {
if ($datos->isMethod('get')) {
return response()->json(['response' => 'This is get method']);
}
return response()->json(['response' => 'This is post method']);
}
-------------0----------------------
-------------0----------------------
答案 3 :(得分：0)
您可以将您的URL添加到VerifyCsrfToken.php中间件。这些网址将从CSRF验证中排除：
protected $except = [ "your url", "your url/abc" ];
答案 4 :(得分：0)
如果您正在寻找确定的答案，那么它是： 如果您在代码中缺少csrf_token（），则会发生此错误 这是我做的，
<h6>ITEMS ORDERED:<a href="#" id="{{$post->identifier}}" onclick="getcart(this.id)">CLICK HERE</a></h6>
<input type="hidden" id="token" value="{{ csrf_token() }}">
现在使用Ajax
<script type="text/javascript">
function getcart(val) {
var alpha=val;
var token=document.getElementById('token').value;
$.ajax({
type:'post',
url:'/private/getcart',
data:{'alpha':alpha,'_token': token},//this _token should be as it is
success:function (result) {
alert(result);
}
});
}
</script>
在我的laravel控制器
中public function getcart(Request $req)
{
return response ("its");
}