Question

我想计算两个日期（时间戳）之间的差异但是以DDd HH24：MI：SS.FF

的特定格式

例如：2d 10：25：30.350

网上有很多例子，但是大多数例子都将天数，小时数，分钟数分开，在不同的列中，而不是将它们全部放在一列中

由于

Answer 1

SQL Fiddle

Oracle 11g R2架构设置：

查询1 ：

WITH times ( start_time, end_time ) AS (
  SELECT TIMESTAMP '2015-01-01 00:00:00', TIMESTAMP '2015-01-03 10:25:30.350' FROM DUAL
  UNION ALL
  SELECT TIMESTAMP '2015-01-01 00:00:00', TIMESTAMP '2015-01-01 09:00:00.000607' FROM DUAL
  UNION ALL
  SELECT TIMESTAMP '2015-03-01 00:00:00', TIMESTAMP '2016-03-01 00:00:00' FROM DUAL
  UNION ALL
  SELECT TIMESTAMP '2015-01-01 00:00:00', TIMESTAMP '2016-01-11 00:00:00' FROM DUAL
)
SELECT TO_CHAR( start_time, 'YYYY-MM-DD HH24:MI:SS.FF6' ) AS start_time,
       TO_CHAR( end_time, 'YYYY-MM-DD HH24:MI:SS.FF6' ) AS end_time,
       REGEXP_REPLACE( end_time - start_time, '^[+-]0*(\d+) 0?(\d+:\d{2}:\d{2}\.\d{3}\d*?)0*$', '\1d \2' ) AS time_difference
FROM   times

<强> Results ：

|                 START_TIME |                   END_TIME |   TIME_DIFFERENCE |
|----------------------------|----------------------------|-------------------|
| 2015-01-01 00:00:00.000000 | 2015-01-03 10:25:30.350000 |   2d 10:25:30.350 |
| 2015-01-01 00:00:00.000000 | 2015-01-01 09:00:00.000607 | 0d 9:00:00.000607 |
| 2015-03-01 00:00:00.000000 | 2016-03-01 00:00:00.000000 |  366d 0:00:00.000 |
| 2015-01-01 00:00:00.000000 | 2016-01-11 00:00:00.000000 |  375d 0:00:00.000 |

Answer 2

如果您知道自己永远不会超过365天，则可以使用有效日期并仅打印数字。我想到这样的事情：

select (case when ts1 - ts2 < 1
             then '000d ' || to_char(date '2000-01-01' + (t1 - t2), 'HH24:MI:SS')
             else to_char(date '2000-01-01' + (t1 - t2) - 1, 'DDDd HH24:MI:SS')
        end)

这会对日期组件进行零填充。如果需要，很容易删除前导零。

Oracle：以特定格式计算两个日期之间的持续时间

2 个答案: