Question

我想将查询结果转换为查询为

的二维数组

SELECT c.name,c.mobile_number,t.service_time 
FROM CUSTOMER AS c
JOIN TRANSACTION AS t ON c.id = t.customer_id
WHERE t.service_date = '$date' 
AND employee_id = '$employee_id

我得到name(varchar),mobile num(int)和时间格式。我写了一些代码，但它不起作用：

$results = array();
echo $num_fields=mysqli_num_fields($array1);
echo $num_rows=mysqli_num_rows($array1);
while($line = mysqli_fetch_array($array1))
{
    for($i=0;$i<$num_rows;$i++)
    {
        for($j=0;$j<$num_fields;$j++)
        {
            $results[$i][$j]=$line[$i][$j];
        }
        }
}

我得到的结果是：

[["k ","a ","r "],["9 ","8 ","7 "],["0 ","2 ",": "]]

输出仅包含第一个字符。我希望每行二维数组都有我的查询结果行。

Answer 1

您只需将结果添加到新数组并将mysqli_fetch_array更改为mysqli_fetch_row：

$results = array();

while ($line = mysqli_fetch_row($array1))
{
  $results[] = $line;
}

或者，您可以使用mysqli_fetch_assoc()制作关联数组（例如$results[0]['name']将成为第一行的name列。

修改

如果存在重复的列名，则可以使用别名：

SELECT one.name AS one_name, two.name AS two_name FROM one INNER JOIN two USING ...

关联数组将具有$result[0]['one_name']和$result[0]['two_name']。

Answer 2

试试这个：

while($line = mysqli_fetch_row($array1))
{
    array_push($result, $line);
}

Answer 3

这应该这样做

$con = mysqli_connect("localhost","my_user","my_password","my_db");
$result = mysqli_query($con, "SELECT * FROM .....");
$rows = array();
if($result){
    while($row = mysqli_fetch_assoc($con, $result)){
        array_push($rows, $row);
    }
    mysqli_free_result($result);
}
var_dump($rows);

将查询结果转换为二维数组

3 个答案: