Question

在我的GameViewController中，我有按钮标签和所有设置。在viewDidLoad（）下，我已将标签和所有内容设置为.hidden = true，我的gameOver内容在我的GameScene文件中，我无法将按钮标签设置为.hidden = true。该按钮被称为backToMenu，如果我在GameViewController中的任何地方键入它，它会识别它，但当我尝试在GameScene中键入backToMenu.hidden = false时，它会给我一个错误。有什么方法可以让我在GameScene中访问它们吗？

GameScene代码：

func gameOver() {

        bigBox.hidden = false
        backToMenu.hidden = false
        scoreLabel.hidden = false

        var alrentSound = NSURL(fileURLWithPath: NSBundle.mainBundle().pathForResource("MenuSelect", ofType: "mp3")!)

        AVAudioSession.sharedInstance().setCategory(AVAudioSessionCategoryPlayback, error: nil)
        AVAudioSession.sharedInstance().setActive(true, error: nil)

        var error: NSError?
        screenTapped = AVAudioPlayer(contentsOfURL: alrentSound, error: &error)
        screenTapped.prepareToPlay()
        screenTapped.stop()

        square1.removeFromParent()
        wallGen.stopWalls()
        //diamondGen.stopDiamonds()
        movingGround.stop()
        square1.stop()
        //square2.stop()


        // save current points label value
        let pointsLabel = childNodeWithName("pointsLabel") as! PPPointsLabel
        let highscoreLabel = childNodeWithName("highscoreLabel") as! PPPointsLabel


        if highscoreLabel.number < pointsLabel.number {
            highscoreLabel.setTo(pointsLabel.number)

            let defaults = NSUserDefaults.standardUserDefaults()
            defaults.setInteger(highscoreLabel.number, forKey: "highscore")
        }

    }

GameVieController代码：

@IBOutlet weak var bigBox: UIImageView!
    @IBOutlet weak var backToMenu: UIButton!
    @IBOutlet weak var scoreLabel: UILabel!



    @IBAction func backToMenuButton(sender: AnyObject) {

        let storyboard = UIStoryboard(name: "Main", bundle: nil)
        let vc = storyboard.instantiateViewControllerWithIdentifier("MainMenuViewController") as! UIViewController
        self.dismissViewControllerAnimated(true, completion: nil)

        var alrentSound = NSURL(fileURLWithPath: NSBundle.mainBundle().pathForResource("MenuSelect", ofType: "mp3")!)

        AVAudioSession.sharedInstance().setCategory(AVAudioSessionCategoryPlayback, error: nil)
        AVAudioSession.sharedInstance().setActive(true, error: nil)

        var error: NSError?
        screenTapped = AVAudioPlayer(contentsOfURL: alrentSound, error: &error)
        screenTapped.prepareToPlay()
        screenTapped.play()

    }

    override func viewDidLoad() {
        super.viewDidLoad()

        bigBox.hidden = true
        backToMenu.hidden = true
        scoreLabel.hidden = true


        // Configure the view
        let skView = view as! SKView


        // store a ref
       // gameScene.gameDelegate = self

        // Create and configure the scene
        gameScene = GameScene(size: skView.bounds.size)
        gameScene?.scaleMode = .AspectFill

        // Present the scene
        skView.presentScene(gameScene)
}

Answer 1

这是因为变量属于不同的类。一种方法，就是声明变量类变量，就像这样

class var myVariable = // whatever

如果你想清理代码，你也可以使用静态getter，比如

static func getMyVariable() -> MyVariableType
{
    return myVariable
}

通过这种方式，可以从任何地方访问变量，并在键入

时访问它们

GameViewController.getMyVariable()

或

GameViewController.myVariable

Answer 2

您需要设置一种方法来访问GameScene中的GameViewController方法。这可以通过创建对GameViewController的引用来完成。为此，我建议您查看这篇文章：Segue in SKScene to UIViewController

访问从GameViewController到GameScene

2 个答案: