我试图主要从一个表中查询数据,但我还需要来自同一数据库中另一个表的两列。我的查询的一部分看起来像这样:
SELECT
'Contact 1' AS "Phone 2 - Type",
Emerg_Phone_1 AS "Phone 2 - Value",
'Contact 2' AS "Phone 3 - Type",
Emerg_Phone_2 AS "Phone 3 - Value",
'Student Cell' AS "Phone 4 - Type",
STUDENTCELL AS "Phone 4 - Value",
FROM STUDENTS JOIN STUDENTS2
所以基本上,除了STUDENTCELL以外,所有五个选择都来自STUDENTS表,但我在同一个查询中需要STUDENTS2表中的一列STUDENTCELL。感谢您提供任何帮助和建议,我对mySQL和oracle都很陌生。
答案 0 :(得分:1)
你几乎得到了解决方案。除了join子句之外。您需要使用common列连接两个表。因此,您可以使用ON Clause
或Using clause
。
b / w的基本差异是
USING子句
如果多个列共享相同的名称但您不想使用所有这些公共列进行连接,则使用USING子句。 USING子句中列出的列在语句中不能包含任何限定符,包括WHERE子句:
ON条款
ON子句用于连接两个表中列名不匹配的表。连接条件将从WHERE子句中的过滤条件中删除:
我将Common列视为ID
。如果两个表都有不同的列名,请使用on
SELECT
'Contact 1' AS "Phone 2 - Type",
Emerg_Phone_1 AS "Phone 2 - Value",
'Contact 2' AS "Phone 3 - Type",
Emerg_Phone_2 AS "Phone 3 - Value",
'Student Cell' AS "Phone 4 - Type",
STUDENTCELL AS "Phone 4 - Value",
FROM STUDENTS JOIN STUDENTS2 ON (STUDENTS.Stud_ID=STUDENTS2.Stud2_ID)
如果两个表具有相同的列名,则使用using
SELECT
'Contact 1' AS "Phone 2 - Type",
Emerg_Phone_1 AS "Phone 2 - Value",
'Contact 2' AS "Phone 3 - Type",
Emerg_Phone_2 AS "Phone 3 - Value",
'Student Cell' AS "Phone 4 - Type",
STUDENTCELL AS "Phone 4 - Value",
FROM STUDENTS JOIN STUDENTS2 using (id);
您可能需要浏览Oracle JOINS和SQL JOINS
答案 1 :(得分:0)
假设var bx1 = $(".bx1");
var bx2 = $(document.querySelectorAll(".bx2"));
是两个表中的公共字段,以下查询应该执行作业
student_id