我是Java的初学者,经过几次书籍学习这门语言之后,我决定编写一个简单的程序,通过用字母替换数字来“加密”字符串,反之亦然。它还没有完成并且有一些相当大的限制,但它应该按原样运行。
代码:
import java.util.Scanner;
class Chiffrator {
public static void main (String args[]) {
Scanner input = new Scanner(System.in); // Initializing keyboard scanner, like arrays (Scanner [name] = new Scanner(System.in)
String initial_code; // Initializing the string into which the text will be entered
System.out.println ("Enter initial code: ");
initial_code = input.next(); // Initializing input process, with syntax [string_name] = [scanner_name].next()
char letters[] = {a,b,c,d,e,f,g,h,i,j};
numbers = new numbers[9];
int i,j,k;
for (i=0; i=9; i++) {
numbers[i] = i;
i++;
}
for (k=0; k=init_code.length(); k++) { // .length() is a method!
if initial_code.contains(numbers))
numbers[k] = letters[k];
else if initial_code.contains(letters))
letters[k] = numbers [k];
k++;
}
System.out.println ("Your chiffred code is " + initial_code);
}
}
它不起作用。当我尝试通过Mac上的终端进行编译时,有2个错误:
Chiffrator.java:24: error: '(' expected
if initial_code.contains(numbers))
^
Chiffrator.java:26: error: '(' expected
else if initial_code.contains(letters))
^
如果我尝试插入这些括号,编译器说我在代码中有20个错误。
Chiffrator.java:12: error: cannot find symbol
char letters[] = {a,b,c,d,e,f,g,h,i,j};
^
symbol: variable a
location: class Chiffrator
Chiffrator.java:12: error: cannot find symbol
char letters[] = {a,b,c,d,e,f,g,h,i,j};
^
symbol: variable b
location: class Chiffrator
Chiffrator.java:12: error: cannot find symbol
char letters[] = {a,b,c,d,e,f,g,h,i,j};
^
symbol: variable c
location: class Chiffrator
Chiffrator.java:12: error: cannot find symbol
char letters[] = {a,b,c,d,e,f,g,h,i,j};
^
symbol: variable d
location: class Chiffrator
Chiffrator.java:12: error: cannot find symbol
char letters[] = {a,b,c,d,e,f,g,h,i,j};
^
symbol: variable e
location: class Chiffrator
Chiffrator.java:12: error: cannot find symbol
char letters[] = {a,b,c,d,e,f,g,h,i,j};
^
symbol: variable f
location: class Chiffrator
Chiffrator.java:12: error: cannot find symbol
char letters[] = {a,b,c,d,e,f,g,h,i,j};
^
symbol: variable g
location: class Chiffrator
Chiffrator.java:12: error: cannot find symbol
char letters[] = {a,b,c,d,e,f,g,h,i,j};
^
symbol: variable h
location: class Chiffrator
Chiffrator.java:12: error: cannot find symbol
char letters[] = {a,b,c,d,e,f,g,h,i,j};
^
symbol: variable i
location: class Chiffrator
Chiffrator.java:12: error: cannot find symbol
char letters[] = {a,b,c,d,e,f,g,h,i,j};
^
symbol: variable j
location: class Chiffrator
Chiffrator.java:13: error: cannot find symbol
numbers = new numbers[9];
^
symbol: variable numbers
location: class Chiffrator
Chiffrator.java:13: error: cannot find symbol
numbers = new numbers[9];
^
symbol: class numbers
location: class Chiffrator
Chiffrator.java:18: error: incompatible types: int cannot be converted to boolean
for (i=0; i=9; i++) {
^
Chiffrator.java:19: error: cannot find symbol
numbers[i] = i;
^
symbol: variable numbers
location: class Chiffrator
Chiffrator.java:24: error: cannot find symbol
for (k=0; k=init_code.length(); k++) // .length() is a method!
^
symbol: variable init_code
location: class Chiffrator
Chiffrator.java:24: error: incompatible types: int cannot be converted to boolean
for (k=0; k=init_code.length(); k++) // .length() is a method!
^
Chiffrator.java:25: error: cannot find symbol
if (cont_let = (initial_code.contains(numbers)))
^
symbol: variable numbers
location: class Chiffrator
Chiffrator.java:26: error: cannot find symbol
numbers[k] = letters[k];
^
symbol: variable numbers
location: class Chiffrator
Chiffrator.java:27: error: incompatible types: char[] cannot be converted to CharSequence
else if (cont_num = (initial_code.contains(letters)))
^
Chiffrator.java:28: error: cannot find symbol
letters[k] = numbers [k];
^
symbol: variable numbers
location: class Chiffrator
Note: Some messages have been simplified; recompile with -Xdiags:verbose to get full output
20 errors
感谢您的帮助!