我有.row-center {
text-align: center;
}
.col-center {
display: inline-block;
border: 1px solid blue;
text-align: left;
float: none;
}
：
@acct_list我试图在银行计划中显示客户＃和帐号＃。我希望我的显示器看起来像这样：
{"account_id"=>1, "customer_id"=>1, "balance"=>0.0, 0=>1, 1=>1, 2=>0.0}
{"account_id"=>2, "customer_id"=>1, "balance"=>1000.0, 0=>2, 1=>nil, 2=>1000.0}
{"account_id"=>3, "customer_id"=>2, "balance"=>9.0, 0=>3, 1=>2, 2=>9.0}
{"account_id"=>4, "customer_id"=>2, "balance"=>0.0, 0=>4, 1=>2, 2=>0.0}
每位客户只能使用客户拥有的帐户总数显示一次。
这就是我的代码：
Customer #1 Account #1 ----- Balance: $0.0
Account #2 ----- Balance: $1000.0
Customer #2 Account #3 ----- Balance: $9.0
Account #4 ----- Balance: $0.0
显示def self.account_info2(acct_list)
account_id_array = []
acct_list.each do |a|
print "\n"
print 'Customer #' + a["customer_id"].to_s + ' Account #' + a["account_id"].to_s + " ----- " + "Balance: $" +
a["balance"].to_s
print "\n"
account_id_array.push(a["account_id"])
end
account_id_array
end
@acct_list = bank.account_list(@man_name, @man_pin)
return account_info2(@acct_list)
：
Customer #答案 0 :(得分：1)
@acct_list = [
{"account_id"=>1, "customer_id"=>1, "balance"=>0.0, 0=>1, 1=>1, 2=>0.0},
{"account_id"=>2, "customer_id"=>1, "balance"=>1000.0, 0=>2, 1=>nil, 2=>1000.0},
{"account_id"=>3, "customer_id"=>2, "balance"=>9.0, 0=>3, 1=>2, 2=>9.0},
{"account_id"=>4, "customer_id"=>2, "balance"=>0.0, 0=>4, 1=>2, 2=>0.0}
]
@acct_list.chunk{|h| h["customer_id"]}
.each do |customer, a| a
.each.with_index do |h, i|
puts \
(("Customer ##{customer}" if i.zero?)).to_s.ljust(11) +
"Account ##{h["account_id"]} ----- Balance: $#{h["balance"]}",
nil
end
end
输出：
Customer #1 Account #1 ----- Balance: $0.0
Account #2 ----- Balance: $1000.0
Customer #2 Account #3 ----- Balance: $9.0
Account #4 ----- Balance: $0.0
答案 1 :(得分：1)
似乎group_by会帮助你。您有一堆帐户数据需要按customer_id分组，然后处理输出。
group_by返回一个散列，其中键是分组项（customer_id'），值是输入数组。您实际上并不需要密钥，因此请在结果上调用.values以使customer_accounts成为一个数组数组，其中每个数组元素包含与一个客户关联的每个帐户的哈希数组。像这样：
[[{"account_id"=>1, "customer_id"=>1, "balance"=>0.0}, {"account_id"=>2, "customer_id"=>1, "balance"=>1000.0}], [{"account_id"=>3, "customer_id"=>2, "balance"=>9.0}, {"account_id"=>4, "customer_id"=>2, "balance"=>0.0}]]
然后迭代customer_accounts以获取每个客户的信息，并使用customer选项迭代每个with_index，以便您只能将Customer #分配给第一个和account_output所需的间距，将所有结果收集到account_list = [{"account_id"=>1, "customer_id"=>1, "balance"=>0.0},
{"account_id"=>2, "customer_id"=>1, "balance"=>1000.0},
{"account_id"=>3, "customer_id"=>2, "balance"=>9.0},
{"account_id"=>4, "customer_id"=>2, "balance"=>0.0}]
def account_info(acct_list)
account_output = ""
customer_accounts = acct_list.group_by { |account| account['customer_id'] }.values
customer_accounts.each do |customer|
customer.each_with_index do |account, index|
if index == 0
account_output += "Customer ##{account['customer_id']} Account ##{account['account_id']} ----- Balance: $#{account['balance']}\n"
else
account_output += " Account ##{account['account_id']} ----- Balance: $#{account['balance']}\n"
end
end
end
print account_output
end
account_info(account_list)
字符串中。
<input type="text" name="entries[]"> /* Input ARRAY */
<input type="text" name="username">
<textarea name="message[]">...</textarea> /* Textarea ARRAY */
答案 2 :(得分：1)
list = [
{"account_id" => 1, "customer_id" => 1, "balance" => 0.0, 0 => 1, 1 => 1, 2 => 0.0},
{"account_id" => 2, "customer_id" => 1, "balance" => 1000.0, 0 => 2, 1 => nil, 2 => 1000.0},
{"account_id" => 3, "customer_id" => 2, "balance" => 9.0, 0 => 3, 1 => 2, 2 => 9.0},
{"account_id" => 4, "customer_id" => 2, "balance" => 0.0, 0 => 4, 1 => 2, 2 => 0.0}
]
list.chunk{|h| h["customer_id"]}.each { |customer_id, customer_data|
msg = "Customer # #{customer_id}"
cust_id_filter = ' ' * (msg.size)
customer_data.each { |h|
print (msg ? msg : cust_id_filter) + " Account # #{h["account_id"]} ---- Balance: $ #{h["balance"]}\n\n"
msg = nil if msg
}
}
你应该输出：
Customer # 1 Account # 1 ---- Balance: $ 0.0
Account # 2 ---- Balance: $ 1000.0
Customer # 2 Account # 3 ---- Balance: $ 9.0
Account # 4 ---- Balance: $ 0.0