Question

我有一个简短的问题，我想获得Type Value“someType” 来自这样的XML结构：

<?xml version="1.0" encoding="utf-8"?>
<UniversalInterchange xmlns="http://www.cargowise.com/Schemas/Universal/2011/11" version="1.1">
    <Header>
    </Header>
    <Body>
        <UniversalShipment xmlns="http://www.cargowise.com/Schemas/Universal/2011/11" version="1.1">
            <Shipment>
                <DataContext>
                    <DataTargetCollection>
                        <DataTarget>
                            <Type>someType</Type>
                        </DataTarget>
                    </DataTargetCollection>
                </DataContext>
                <FileType>
                  <SecondType>not this type</SecondType>
                </FileType>
      </Shipment>
     </UniversalShipment>
    </Body>
</UniversalInterchange>

我尝试了更多可能的解决方案，但没有给我类型

XmlDocument xml = new XmlDocument();
xml.LoadXml(myXmlString); 

XmlNodeList xnList = xml.SelectNodes("/UniversalInterchange/Body/UniversalShipment/Shipment/DataContext/DataTargetCollection/DataTarget");

foreach (XmlNode xn in xnList)
{
   string type = xn["Type"].InnerText;
   Console.WriteLine("Name: {0} {1}", type);
}

什么错了？

Answer 1

正如其他人所说，XDocument是可行的方法。还有一个命名空间，这意味着你需要做这样的事情：

var xDoc = XDocument.Parse(xmlString);

XNamespace ns = "http://www.cargowise.com/Schemas/Universal/2011/11";

var value = xDoc
    .Element(ns + "UniversalInterchange")
    .Element(ns + "Body")
    .Element(ns + "UniversalShipment")
    .Element(ns + "Shipment")
    .Element(ns + "DataContext")
    .Element(ns + "DataTargetCollection")
    .Element(ns + "DataTarget")
    .Element(ns + "Type")
    .Value;

从xml文件中获取XML值

1 个答案: