我有两节课。首先是二等领域。
class A {
@JsonSerializer(using = CustomBSerializer.class)
private B b;
}
class B {
...
}
我有两个自定义序列化器:
class CustomBSerializer extends JsonSerializer<B> {
...
}
class CustomASerializer extends JsonSerializer<A> {
@Override
public void serialize(A a, JsonGenerator jgen, SerializerProvider provider)
throws IOException, JsonProcessingException {
jgen.writeStartObject();
//write here
jgen.writeEndObject();
}
}
我应该在CustomASerializer
中添加哪种方法而不是评论,以便使用b
来编写字段CustomBSerializer
的序列化值?
答案 0 :(得分:3)
您可以使用writeObjectField
方法。如果存在,Jackson
应使用默认或自定义序列化程序。
以下示例:
import com.fasterxml.jackson.core.JsonGenerator;
import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.databind.JsonSerializer;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.SerializerProvider;
import com.fasterxml.jackson.databind.annotation.JsonSerialize;
import java.io.IOException;
import java.util.Date;
public class Main {
public static void main(String[] args) throws Exception {
B b = new B();
b.setProperty("Value");
A a = new A();
a.setB(b);
ObjectMapper mapper = new ObjectMapper();
System.out.println(mapper.writerWithDefaultPrettyPrinter().writeValueAsString(a));
}
}
@JsonSerialize(using = ASerializer.class)
class A {
private B b;
public B getB() {
return b;
}
public void setB(B b) {
this.b = b;
}
}
class ASerializer extends JsonSerializer<A> {
@Override
public void serialize(A value, JsonGenerator gen, SerializerProvider serializers) throws IOException, JsonProcessingException {
gen.writeStartObject();
gen.writeStringField("now", new Date().toString());
gen.writeObjectField("b", value.getB());
gen.writeEndObject();
}
}
@JsonSerialize(using = BSerializer.class)
class B {
private String property;
public String getProperty() {
return property;
}
public void setProperty(String property) {
this.property = property;
}
}
class BSerializer extends JsonSerializer<B> {
@Override
public void serialize(B value, JsonGenerator gen, SerializerProvider serializers) throws IOException, JsonProcessingException {
gen.writeStartObject();
gen.writeStringField("p", value.getProperty());
gen.writeEndObject();
}
}
打印:
{
"now" : "Wed Aug 26 22:27:08 CEST 2015",
"b" : {
"p" : "Value"
}
}
答案 1 :(得分:0)
您并非总是有权访问类代码,也不会总是有可能修改A或B类以放置批注@JsonSerialize(使用= BSerializer.class)。在这些情况下,您将需要在CustomASerializer中调用CustomBSerializer,这也是问题首先提出的问题。这是这样做的方法:
class CustomASerializer extends JsonSerializer<A> {
@Override
public void serialize(A a, JsonGenerator jgen, SerializerProvider provider) throws IOException, JsonProcessingException {
final ObjectMapper mapper = (ObjectMapper)jgen.getCodec();
SimpleModule module = new SimpleModule("CustomBSerializer");
module.addSerializer(B.class, new CustomBSerializer());
mapper.registerModule(module);
jgen.writeStartObject();
mapper.writeValue(jgen, a.getB());
jgen.writeEndObject();
}
}