Question

当我尝试运行我的应用时出现此错误：

Terminating app due to uncaught exception 'NSRangeException', reason: '*** -[__NSArrayM objectAtIndex:]: index 9223372036854775807 beyond bounds [0 .. 0]'

我真的不知道我的错误是什么。我还注意到，当我在我的表中存储一个dateTime数据时，它用括号括起来，引用就像上午9:47一样（“上午9:47”）。我是Xcode的新手。我已经一周了。这是我的代码：

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {
static NSString *simpleTableIdentifier = @"SimpleTableCell";

SimpleTableCell *cell = (SimpleTableCell *)[tableView dequeueReusableCellWithIdentifier:simpleTableIdentifier];
if (cell == nil)
{
    NSArray *nib = [[NSBundle mainBundle] loadNibNamed:@"SimpleTableCell" owner:self options:nil];
    cell = [nib objectAtIndex:0];
}

NSInteger indexOfAlarm = [self.dbManager.arrColumnNames indexOfObject:@"Time"];
   cell.timeLabel.text = [NSString stringWithFormat:@"%@",[[self.arrAlarmInfo objectAtIndex:indexPath.row]objectAtIndex:indexOfAlarm] ];
    return cell;
}

Answer 1

9223372036854775807的值是常量NSNotFound。它表示搜索的实例在数组中不存在。要检查它，请添加if - 声明：

NSInteger indexOfAlarm = [self.dbManager.arrColumnNames indexOfObject:@"Time"];
if(indexOfAlarm != NSNotFound) // <-
{
   cell.timeLabel.text = [NSString stringWithFormat:@"%@",[[self.arrAlarmInfo objectAtIndex:indexPath.row]objectAtIndex:indexOfAlarm] ];
}
return cell;

如果您希望@"Time"始终在数组中，您必须找出原因，为什么它不存在。

Answer 2

更改此代码

 NSInteger indexOfAlarm = [self.dbManager.arrColumnNames indexOfObject:@"Time"];

 cell.timeLabel.text = [NSString stringWithFormat:@"%@",[[self.arrAlarmInfo objectAtIndex:indexPath.row]objectAtIndex:indexOfAlarm] ];

以

NSNumber *indexOfAlarm = [self.dbManager.arrColumnNames indexOfObject:@"Time"]; cell.timeLabel.text = [NSString stringWithFormat:@"%@",[[self.arrAlarmInfo objectAtIndex:indexPath.row]objectAtIndex:indexOfAlarm.intValue] ];

[__NSArrayM objectAtIndex：]：索引9223372036854775807超出界限[0 .. 0]'

2 个答案: