Question

我正在尝试解决可能导致此问题的问题。我是Java和BlueJ的新手，但已经看了好几个小时，无法弄清楚导致问题的原因。继续收到错误消息“不兼容的类型：Plasterer无法转换为Apprentice”。非常感谢任何帮助。

//程序的目的：创建一个混合数组来容纳2个不同的Apprentice对象 - Plasterer和Carpenter //泥水匠和木匠 //然后将每个对象的所有细节显示在屏幕上。

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学徒班就是这样

public class MixedLists
{

  public static void main(String args[])
  {

    //Declaration of object list to hold 2 student objects
    Apprentice [] apprenticeList = new Apprentice[2];

    ////////////////////////////////////////////////////////////////////
    //Plasterer
    //Taking in values
    String NameIn, NumberIn, AddressIn, StudentIDIn, EmployerNameIn, FinalSem1GradeIn;

    System.out.println("Entering data for Plasterer");
    //Apprentice class attributes
    System.out.print("\tEnter Name:                   ");
    NameIn = EasyScanner.nextString();

    System.out.print("\tEnter telephone number:       ");
    NumberIn = EasyScanner.nextString();

    System.out.print("\tEnter Address:                ");
    AddressIn = EasyScanner.nextString();

    System.out.print("\tEnter student id:             ");
    StudentIDIn = EasyScanner.nextString();      

    //Plasterer class attributes
    System.out.print("\tEnter in Employer Name:         ");
    EmployerNameIn = EasyScanner.nextString();

    System.out.print("\tEnter Final Semester 1 Grade:    ");
    FinalSem1GradeIn = EasyScanner.nextString();

    //Initializing what is referenced by position 0 of the object list with a plasterer object
    apprenticeList[0]=new Plasterer(NameIn, NumberIn, AddressIn, StudentIDIn, EmployerNameIn, FinalSem1GradeIn);

    System.out.println("\n");

    /////////////////////////////////////////////////////////////////   
    //Carpenter
    String NameIn1,AddressIn1,Number1,StudentID1;
    //additional variables
    String awardSought,specialisation;
    double gpaModuleGrade, industrialExperienceMark;

    //Entering values for Carpenter
    System.out.println("Entering data for Carpenter");
    //Apprentice class attributes
    System.out.print("\tEnter Name:                   ");
    NameIn1 = EasyScanner.nextString();

    System.out.print("\tEnter telephone number:       ");
    Number1 = EasyScanner.nextString();

    System.out.print("\tEnter Address:                ");
    AddressIn1= EasyScanner.nextString();

    System.out.print("\tEnter student id:             ");
    StudentID1= EasyScanner.nextString();

    //Carpenter class attributes    
    System.out.print("\tEnter award sought:           ");
    awardSought = EasyScanner.nextString();
    System.out.print("\tEnter specialist area:        ");
    specialisation = EasyScanner.nextString();

    //Carpenter class attributes
    System.out.print("\tEnter GPA Module Grade:       ");
    gpaModuleGrade = EasyScanner.nextString();
    System.out.print("\tEnter industrial experience Grade: ");
    industrialExperienceMark = EasyScanner.nextString();

    //Initializing what is referenced by position 1 of the object list with a Carpenter object
    apprenticeList[1]=new Carpenter(NameIn1, AddressIn1, Number1, StudentID1,awardSought,specialisation, gpaModuleGrade,industrialExperienceMark);

    System.out.println("\n");

    ////////////////////////////////////////////////////////////////////
    //for loop to display out contents of mixed object array
    //Display out all information associated with Carpenter, Carpenter and CabinetMaker

    System.out.println("Award Details for all Apprentices in the System\n"); 
    for(int i = 0; i < apprenticeList.length; i++)
    {
        System.out.println(apprenticeList[i].printAwardDetails());
    }

  }
}

Answer 1

您需要使用继承。

创建一个名为“Worker”的类，然后Plasterer和Apprentice都应该继承该类。然后，您可以获得包含Plasterers和Apprentice的工人列表。

或者如果“学徒”只是一种泥水匠，让学徒继承泥水匠（或者如果泥水匠是一种学徒则相反）

不兼容的类型：对象无法转换为另一个对象？

1 个答案: