在python-kwargs错误中,dict不可调用

时间:2015-08-25 15:49:10

标签: python dictionary kwargs

我有以下代码从yaml读取:

if 'parameters' in options:
    for name, parameter_options in options['parameters'].items():
        make_parameters = injector.parameters()
        print parameter_options
        parameter_injected = make_parameters(**parameter_options)
        parameters = cft.add_parameters()
        parameters(key, **parameter_injected)

给了我错误:

parameter_injected = make_parameters(**parameter_options) TypeError: 'dict' object is not callable

parameter_options是从yaml读取并打印出来的字典:

{'constraint_description': 'Malformed input-Parameter MyParameter must only contain upper and lower case letters', 'min_length': 12, 'description': 'to do some stuff', 'default': '10.201.22.33', 'max_value': 34, 'min_value': 12, 'allowed_values': ['sdd', 'asas'], 'max_length': 23, 'allowed_pattern': '[A-Za-z0-9]+', 'no_echo': True, 'type': 'String'}

所以,当我这样做时,**参数不应该只是将dict转换为费用吗?

1 个答案:

答案 0 :(得分:0)

我的不好,纠正了我的代码:

if 'parameters' in options:
    for name, parameter_options in options['parameters'].items():
        parameter_injected = injector.parameters(**parameter_options)
        parameters = cft.add_parameters(name, **parameter_injected)