Question

我正在向Oracle移植H2 UPDATE / SELECT语句，并且遇到了我在诊断时遇到问题的语法问题。

我有3个表，Users，Cars和Trips。他们看起来像：

SELECT * FROM USERS;
+------------+----+--------+
|  USERNAME  | ID | CAR_ID |
+------------+----+--------+
| John.Smith |  1 |     5  |
| Abby.Smith |  2 |     6  |
+------------+----+--------+

SELECT * FROM CARS;
+----+--------+-------+
| ID |  MAKE  | COLOR |
+----+--------+-------+
|  5 | Subaru | Green |
|  6 | Honda  | Red   |
+----+--------+-------+

SELECT * FROM TRIPS;
+----+------------+---------+
| ID |  USERNAME  | MILEAGE |
+----+------------+---------+
|  8 | Abby.Smith |      87 |
|  9 | John.Smith |      23 |
+----+------------+---------+

但是，我们现在决定向Trips添加一个新列，并且（仅）跟踪汽车模型而不是用户。作为中间结果，在放弃USERNAME列之前，我正试图实现：

+----+------------+---------+-----------+
| ID |  USERNAME  | MILEAGE | CAR_MODEL |
+----+------------+---------+-----------+
|  8 | Abby.Smith |      87 |     Honda |
|  9 | John.Smith |      23 |    Subaru |
+----+------------+---------+-----------+

我的（非功能性）陈述如下：

WITH USER_MODELS AS
(SELECT USERNAME, MAKE FROM USERS JOIN CARS ON (USERS.CAR_ID = CARS.ID))
UPDATE TRIPS SET CAR_MODEL =
    SELECT MAKE FROM USER_MODELS
    WHERE TRIPS.USERNAME = USER_MODELS.USERNAME

但是，我收到的语法错误是：

UPDATE TRIPS SET CAR_MODEL =
*
ERROR at line 3:
ORA-00928: missing SELECT keyword

这让我失去了一个循环。 SELECT语句紧跟在UPDATE之后，WITH本身前面有SELECT子句，似乎包含格式正确的$kernel = $app->make(Illuminate\Contracts\Http\Kernel::class);。

Answer 1

可以这样做，但是你需要将WITH子句放在子查询中：

timer = [NSTimer scheduledTimerWithTimeInterval:60.0f target:self selector:@selector(timeUpdated) userInfo:nil repeats:YES];

Oracle UPDATE使用包含JOIN的SELECT语句

1 个答案: