使用php使用逗号功能尾随零

Question

嗨我在javascript中的代码工作正常，但我想在php语言中使用相同的功能我在互联网上找到不同的来源，但没有获得成功。

Javascript代码：

Number.prototype.formatMoney = function(c, d, t){
    var n = this,
    c = isNaN(c = Math.abs(c)) ? 2 : c,
    d = d ? "." : d,
    t = t ? "," : t,
    s = n < 0 ? "-" : "",
    i = parseInt(n = Math.abs(+n || 0).toFixed(c)) + "",
    j = (j = i.length) > 3 ? j % 3 : 0;
    return s + (j ? i.substr(0, j) + t : "") + i.substr(j).replace(/(\d{3})(?=\d)/g, "$1" + t) + (c ? d + Math.abs(n - i).toFixed(c).slice(2) : "");
};
function trailingZerosWithComma() {
    var costAmount = $("#costAmount").val();
    if(costAmount != "") {
         var costAmountReplace = parseFloat(costAmount.replace(/\,/g,''));
         $("#costAmount").val((costAmountReplace).formatMoney(2, '.', ','));
    }
}
<input type="text" name="costAmount" id="costAmount" onblur="trailingZerosWithComma();">

但我需要在php

中使用它

Number.prototype.formatMoney = function(c, d, t){
        var n = this,
        c = isNaN(c = Math.abs(c)) ? 2 : c,
        d = d ? "." : d,
        t = t ? "," : t,
        s = n < 0 ? "-" : "",
        i = parseInt(n = Math.abs(+n || 0).toFixed(c)) + "",
        j = (j = i.length) > 3 ? j % 3 : 0;
        return s + (j ? i.substr(0, j) + t : "") + i.substr(j).replace(/(\d{3})(?=\d)/g, "$1" + t) + (c ? d + Math.abs(n - i).toFixed(c).slice(2) : "");
    };
var costAmountReplace = parseFloat(costAmount.replace(/\,/g,''));