从listview android解析删除对象

时间:2015-08-25 06:30:02

标签: java android listview parse-platform

我正在使用Parse on app将推送发送给拥有该应用的其他用户。我希望用户能够从列表中删除已添加的朋友。我设法修改了一些代码,但它删除了列表中的第一项。如何修改它以仅删除所选用户?

                    @Override
                    public void onPositive(MaterialDialog dialog) {
                        ParseQuery<ParseObject> query = ParseQuery.getQuery("Friend");
                        query.whereEqualTo("user", mCurrentUser);
                        query.findInBackground(new FindCallback<ParseObject>() {
                            @Override
                            public void done(List<ParseObject> list, ParseException e) {
                                if (list.size() != 0)
                                    Log.v("TAG", "sizzzze" + list.size());     //Showing 1
                                list.get(0).deleteInBackground(new DeleteCallback() {
                                    @Override
                                    public void done(ParseException e) {
                                        if (e == null) {
                                            Toast.makeText(getBaseContext(), "Deleted Successfully!", Toast.LENGTH_LONG).show();
                                        } else {
                                            Toast.makeText(getBaseContext(), "Cant Delete Tickle!" + e.toString(), Toast.LENGTH_LONG).show();
                                        }

                                    }
                                });
                            }
                        });
                    }

更新: @haint

// Listener for ListView item clicks
private class FriendLongClickListener implements AdapterView.OnItemLongClickListener {

    @Override
    public boolean onItemLongClick(AdapterView<?> parent, View view, int position, long id) {
        final String friend = mUserFriends.get(position).getString("user");
        new MaterialDialog.Builder(MainActivity.this)
                .title("Remove"+" "+mUserFriends.get(position).getUsername().toUpperCase() + "?")
                .content("Do you really want to remove" + " " + mUserFriends.get(position).getUsername().toUpperCase() + " " + "from your friend list?")
                .positiveText(R.string.dialog_yes)
                .negativeText(R.string.dialog_no)
                .callback(new MaterialDialog.ButtonCallback() {
                    @Override
                    public void onPositive(MaterialDialog dialog) {
                        ParseQuery<ParseObject> query = ParseQuery.getQuery("Friend");
                        query.whereEqualTo("user", mCurrentUser);
                        query.findInBackground(new FindCallback<ParseObject>() {
                            @Override
                            public void done(List<ParseObject> list, ParseException e) {
                                if (list.size() != 0)
                                    Log.v("TAG", "sizzzze" + list.size());     //Showing 1
                                list.get(0).deleteInBackground(new DeleteCallback() {
                                    @Override
                                    public void done(ParseException e) {
                                        if (e == null) {
                                            Toast.makeText(getBaseContext(), "Deleted Successfully!", Toast.LENGTH_LONG).show();
                                        } else {
                                            Toast.makeText(getBaseContext(), "Cant Delete Tickle!" + e.toString(), Toast.LENGTH_LONG).show();
                                        }

                                    }
                                });
                            }
                        });
                    }

                        @Override
                    public void onNegative(MaterialDialog dialog) {
                    }
                })
                .show();
        return true;
    }

}

0 个答案:

没有答案
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