Question

以下是此问题的后续内容......

Python & Tkinter - buttons command to set label textvariable issue

我已经完成了计算器，但问题出在这里：

我的按钮都是使用for循环构建的;包括功能按钮。我喜欢这样的事实，即代码很短，并不想真正去除for-loop中的所有功能按钮，但我可能不得不解决问题，我没有得到为该部门返回的浮点值两个整数。

根据这个计算器，

即12/8 = 1。

任何聪明的想法如何在不删除for循环的运算符的情况下做到这一点？

from Tkinter import *
import Tkinter as tk
import tkMessageBox

# main window
root = Tk()
root.title('Calculator')

# button set
buttons = ['1','2','3','4','5','6','7','8','9','0','+','-','/','*','.']

sum_value = StringVar()

def appear(x):
    return lambda: output_window.insert(END,x)

# output window
output_window = tk.Entry(root, textvariable=sum_value, width=20, font = 'courier 10')
output_window.grid(row=0, columnspan=3, sticky=(E,W))

def equals():
    try:
        result = eval(output_window.get())
    except:
        result = 'INVALID'

    output_window.delete(0,END)
    output_window.insert(0,result)

def refresh():
    output_window.delete(0,END)

# button creation
r=1
c=0

for i in buttons:
    if c < 2:
        tk.Button(root, text = i, command = appear(i), pady = 3).grid(row = r, column = c, sticky = (N,S,E,W))        
        c += 1
    else:
        tk.Button(root, text = i, command = appear(i), pady = 3).grid(row = r,column = c,sticky = (N,S,E,W))
        r  += 1
        c = 0

# clear and equal button
equal = tk.Button(root,text='=',padx = 5, pady=3, command=equals)
equal.grid(row=6,column=0,sticky=(N,S,E,W))

clear = tk.Button(root,text='CLEAR',padx = 5, pady=3,command = refresh)
clear.grid(row=6,column=1, columnspan = 2,sticky=(N,S,E,W))


#menu
menubar = Menu(root)

def quit1():
    if tkMessageBox.askokcancel("Quit","Are you sure you want to quit?"):
        root.destroy()

viewMenu = Menu(menubar)
viewMenu.add_command(label='Quit', command = quit1)
menubar.add_cascade(label="Home", menu=viewMenu)


root.config(menu=menubar)
root.mainloop()

使用Tkinter计算器的按钮初始化来获取整数和浮点数

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