Question

错误显示我的代码有无效参数... 任何人都可以告诉我什么是错的？我应该将图像分配给clientID。

private void button1_Click(object sender, EventArgs e)
{
        MySqlConnection conn = new MySqlConnection(mycon);
        MySqlCommand cmd = new MySqlCommand("SELECT clientImage FROM client WHERE clientID='" + label2.Text + "'", conn);

        conn.Open();
        MySqlDataReader myReader = null;
        myReader = cmd.ExecuteReader();

        while (myReader.Read())
        {
            byte[] imgg = (byte[])(myReader["clientImage"]);
            if (imgg == null)
            {
                pictureBox1.Image = null;
            }
            else
            {
                MemoryStream mstream = new MemoryStream(imgg);
                pictureBox1.Image = System.Drawing.Image.FromStream(mstream);
            }
        }
        conn.Close();
}

Answer 1

此代码有效。 MySql Wamp。

using System.IO;

string appPath = Path.GetDirectoryName(Application.Executable) + @"/student Images/";
string imagename;

//put this code below to load form.
getimage();
if(File.Exist(appPath + imagename)
{
PictureBox1.Image = Image.FromFile(appPath + imagename);
}
else
{
PictureBox1.Image = Properties.Resources.Image_notfound;
}

private void getimage()
{
MySqlConnection connect = new MySqlConnection(con);
MySqlCommand cmd = new MySqlCommand("SELECT PictureName as 'pic' FROM userprofile where ID='" + datagrid.CurrentRow.Cells["ID"].ToString() + "'");
cmd.CommandType = CommandType.Text;
cmd.Connection = connect;
connect.Open();
Try
{
MySqlDataReader dr = cmd.ExecuteReader();
while(dr.Read())
{
imagename = dr.GetString("pic");
}
dr.Close();
}
catch(Exception ee)
{
Console.WriteLine(ee.ToString());
}
finally
{
connect.Close();
}

如何在c＃中从数据库中检索图像

1 个答案: