Question

我想获得第三列类似值的单列。这是我现在的询问。我怎么能得到这个

8   31-Jul-2015 10:02 AM    77
8   31-Jul-2015 11:24 AM    77
8   01/Aug/2015 11:04 AM    79
8   03/Aug/2015 10:12 AM    80
8   03/Aug/2015 12:25 PM    80
8   21/Aug/2015 04:32 PM    83
8   22/Aug/2015 05:39 PM    85
8   24/Aug/2015 09:56 AM    86
8   24/Aug/2015 09:59 AM    86
8   24/Aug/2015 09:59 AM    86

我的查询是

@employeeId int=8,
    @datefrom date=null,
    @dateto date=null

AS
BEGIN
    -- SET NOCOUNT ON added to prevent extra result sets from
    -- interfering with SELECT statements.
    SET NOCOUNT ON;

     --Insert statements for procedure here


select 
x.employee_Id,
x.punchin,
x.attendanceMasterId

from 
(       
        select atin.punchin,inam.employee_Id,atin.attendanceMasterId

        from dbo.tblAttendanceDetails atin

         left join dbo.tblAttendanceMaster inam on inam.record_Id=atin.attendanceMasterId 

         left join tblEmployeeJobDetails ejd on ejd.recordId=inam.employee_Id

        where ((isnull(@employeeId,0)=0 or ejd.recordId=@employeeId))

) x

END

Answer 1

您可以通过连接所有三列来实现此目的，如： -

select (cast(column1 as varchar) +' '+ 
cast(column2 as varchar)+' '+cast(column3 as varchar)) 
as '' from table_name

用于在子查询中使用group by获取单行相似列值的SQL Query

1 个答案: