Question

我在业余时间一直在制作一个愚蠢的小卡片游戏，并决定使用XML来存储卡片信息，因为我最近完成了一个XML课程。

问题是，课堂上使用的方法似乎不再起作用，也没有我在这里看到的替代方案。他们都没有抛出异常，所有人都可以看到文件，但拒绝从中提取任何内容。

XDocument，XmlDocument和XPathDocument看到文件就好了，所以问题不在那里。但是，XPathNavigator.Select（）和XDocument.XPathSelectElements（）根本不返回任何内容。

我目前的Cards.xml：

<?xml version="1.0" encoding="utf-8" ?>
<Cards xmlns="http://tempuri.org/CardSchema.xsd">
  <Card>
    <Name>Emperor Heavy Tank</Name>
    <Type>Attack</Type>
    <Colour>Red</Colour>
    <Distinctions>
      <Distinction>Weapon</Distinction>
      <Distinction>Machine</Distinction>
    </Distinctions>
    <Health>25</Health>
    <Power>12</Power>
    <Ability>
      <Name>Repair Crew</Name>
      <Description>Heal for 4 HP, and apply 2 armour on the card if it is lacking. Increase turn wait for both skills by 1.</Description>
      <PowerUse>1</PowerUse>
      <TurnWait>1</TurnWait>
    </Ability>
    <Ability>
      <Name>High Caliber</Name>
      <Description>Deals 6 dmg to target, +2 if target is a Machine. If any adjacent cards are of the same colour, they recieve 3 spill damage, 1 otherwise. 4 turn wait.</Description>
      <PowerUse>5</PowerUse>
      <TurnWait>4</TurnWait>
    </Ability>
  </Card>
  <Card>
    <Name>Flamethrower</Name>
    <Type>Attack</Type>
    <Colour>Red</Colour>
    <Distinctions>
      <Distinction>Machine</Distinction>
      <Distinction>Weapon</Distinction>
    </Distinctions>
    <Health>13</Health>
    <Power>20</Power>
    <Ability>
      <Name>Roar of the Wheels</Name>
      <Description>All player ATK cards (besides Flamethrower) recieve +1 POW if the enemy doesn't have a red card in play. 1 turn wait.</Description>
      <PowerUse>2</PowerUse>
      <TurnWait>1</TurnWait>
    </Ability>
    <Ability>
      <Name>Flame Artillery</Name>
      <Description>Deals 7 dmg to non-red target. If target is red, deals 3 dmg, and does 2 dmg to both adjacent cards. 3 turn wait.</Description>
      <PowerUse>5</PowerUse>
      <TurnWait>3</TurnWait>
    </Ability>
  </Card>
</Cards>

尝试＃1：

XmlDocument Document = new XmlDocument();
Document.Load("Cards.xml");

var Navigator = Document.CreateNavigator();
var Expression = Navigator.Compile("/Cards/Card");
var Iterator = Navigator.Select(Expression);

while (Iterator.MoveNext()) // nothing to iterate through, so it just skips to the next statement immediately
{
    var HelpNavigator = Iterator.Current.Clone();
    Console.WriteLine(HelpNavigator.Value);
}

Console.ReadKey();

尝试＃2：

XPathDocument Document = new XPathDocument("Cards.xml");
var Navigator = Document.CreateNavigator();
var Expression = XPathExpression.Compile("//Card/*");
var Iterator = Navigator.Select(Expression);

do
{
    var InnerIterator = Iterator.Current.SelectChildren(XPathNodeType.Text);
    do
    {
        Console.WriteLine(InnerIterator.Current.Value);
    } while (InnerIterator.MoveNext());
} while (Iterator.MoveNext());

Console.ReadKey();

尝试＃3：

XDocument Document = XDocument.Load("Cards.xml");
var Elements = Document.XPathSelectElements("//Card/child::*");
foreach (var item in Elements) // and again, nothing
{
    Console.WriteLine("{0}: {1}", item.Name.ToString(), item.Value);
}

Console.ReadKey();

我甚至轮换了一些XPath样式，以防万一 - 但他们应该都达到同样的目的。

Answer 1

好的，我使用了@Corak提供的方法：

XDocument Document = XDocument.Load("Cards.xml");
var xns = XNamespace.Get("http://tempuri.org/CardSchema.xsd");
var Elements = Document.Root.Elements(xns + "Card");
foreach (var Card in Elements)
{
    // Process card information here

    foreach (var item in Card.Elements())
    {
        Console.WriteLine("{0}: {1}", item.Name.ToString(), item.Value);
    }
}

Console.ReadKey();

这将为我提供文件中所需的所有信息。

没有一种XML解析方法适合我

1 个答案: