Question

此代码按月和年显示记录例如：

2015年7月
2015年8月
2015年9月

这里我的代码正常运作。

<?php
  $qry = "SELECT count(*), monthname(curdate), year(curdate) FROM cswd_records GROUP BY month(curdate), year(curdate)";
   $run = mysql_query($qry) or die(mysql_error()); 
  ?>
</div>
<div class="col-md-3"></div>
<div class="col-md-6">
<Center><span class="impactsoc">Total Applicants by Month</span></center><br>
<table class="table table-striped table-bordered table-hover table-condensed" >
  <thead>
    <tr>
<th># of Applicants</th>
<th>Month</th>
    </tr>
  </thead>
  <tbody>       
    </tr>
    <?php while ($row = mysql_fetch_array($run)) {?>
        <tr>
        <td width="250"><h5><?php echo $row['count(*)']; ?></h5></td>
         <td width="250"><h5><a href="month.php?monthyear=<?php echo $row['monthname(curdate)'];?>-<?php echo $row['year(curdate)'];?>"><?php echo $row['monthname(curdate)'];?>&nbsp;&nbsp;<?php echo $row['year(curdate)'];?></h5></a> </td>
      </tr>
      <tr>
        <td colspan="2"><center><h4><i>Total Applicants:</i><font color="red"> <?php echo $row['count(*)']; ?></font></h4></center></td>
      </tr><?php }?>

</table>

这是我的问题。如何显示2015年7月的所有列表（如果我只想显示月份或年份，它就可以工作。我不知道它的2值。）

网址价值：

month.php?monthyear=August-2015

如果只有1个值，这个就可以了。如何显示月份和年份？

$myr = $_GET['monthyear']; //getting the details by link(a href)
    $result = $db->prepare("SELECT * FROM cswd_records WHERE monthname(curdate)='". mysql_real_escape_string($myr) ."'");

Answer 1

为什么不把年份放在

$result = $db->prepare("SELECT * FROM cswd_records WHERE
monthname(curdate)='". mysql_real_escape_string($myr) ."' 
AND year(curdate)='". mysql_real_escape_string($myr) ."'");

修改

$myr = explode("-", $_GET['monthyear']);

使用

$result = $db->prepare("SELECT * FROM cswd_records WHERE
monthname(curdate)='". mysql_real_escape_string($myr[0]) ."' 
AND year(curdate)='". mysql_real_escape_string($myr[1]) ."'");

Answer 2

解决方案：

 $result = $db->prepare("SELECT * FROM cswd_records WHERE monthname(curdate) ='". mysql_real_escape_string($myr) ."' 
AND year(curdate)='". mysql_real_escape_string($myr1) ."'");

感谢@Harshit Shrivastava

如何显示显示日期名称和记录的记录一年使用这种方法

2 个答案: