我已经设置了整个SQL数据库。
个人资料页面已经有效,但现在它只显示登录人员的个人资料信息。
我想设置它以便它是profile.php?ID = 1所以任何人都可以查看数据库中的任何配置文件。
我尝试了几个不同的教程,并在这里查看了给别人的答案,但我仍然无法让它工作。我被卡住了。
<?php
session_start();
if (!function_exists("GetSQLValueString")) {
function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "")
{
if (PHP_VERSION < 6) {
$theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue;
}
$theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue);
switch ($theType) {
case "text":
$theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
break;
case "long":
case "int":
$theValue = ($theValue != "") ? intval($theValue) : "NULL";
break;
case "double":
$theValue = ($theValue != "") ? doubleval($theValue) : "NULL";
break;
case "date":
$theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
break;
case "defined":
$theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue;
break;
}
return $theValue;
}
}
$colname_Recordset1 = "-1";
if (isset($_SESSION['MM_Username'])) {
$colname_Recordset1 = $_SESSION['MM_Username'];
}
mysql_select_db($database_login_form, $login_form);
$query_Recordset1 = sprintf("SELECT * FROM users WHERE username = %s", GetSQLValueString($colname_Recordset1, "text"));
$Recordset1 = mysql_query($query_Recordset1, $login_form) or die(mysql_error());
$row_Recordset1 = mysql_fetch_assoc($Recordset1);
$totalRows_Recordset1 = mysql_num_rows($Recordset1);
include 'logout_script.php';
?>
答案 0 :(得分:1)
尝试以下代码。我注意到了重要的部分:
$ ./kbox3/bin/kbox_shell
fakechroot: dlopen: undefined symbol: dlopen
答案 1 :(得分:0)
我能够通过将代码从MM_Username更改为id来解决此问题,并且能够从那里插入适当的详细信息。谢谢!