$array[key][key]...[key]
替换为
$array['key']['key']...['key']
我设法只为数组的第一个关键字添加引号。
\$([a-zA-Z0-9]+)\[([a-zA-Z_-]+[0-9]*)\]替换为\$\1\[\'\2\3\'\]
答案 0 :(得分：1)
您可以使用不执行递归但连续匹配的正则表达式：
containment请参阅IDEONE demo
正则表达式//Access the resize function of containment
$(".box").resizable('instance').plugins.resize[0][1] = function (event) {
...
//This is the only change to the original function.
//It looks at the direction of the resize.
//If axis is left or top then the calculations are made with position
//instead of width, with an adjusment based on grid size
if ((/w/.test(that.axis) ? that.position.left - 10 : woset) + that.size.width >= that.parentData.width) {
that.size.width = that.parentData.width - woset;
if (pRatio) {
that.size.height = that.size.width / that.aspectRatio;
continueResize = false;
}
}
if ((/n/.test(that.axis) ? that.position.top - 10 : hoset) + that.size.height >= that.parentData.height) {
that.size.height = that.parentData.height - hoset;
if (pRatio) {
that.size.width = that.size.height * that.aspectRatio;
continueResize = false;
}
}
...
}
匹配所有方括号子串（将其内容捕获到第2组）（使用$re = '/(\$\w+|(?!^)\G)\[([^]]*)\]/';
$str = "\$array[key][key][key]";
$subst = "$1['$2']";
$result = preg_replace($re, $subst, $str);
echo $result;
），它们位于(\$\w+|(?!^)\G)\[([^]]*)\]子字符串之后（由于{{1}连续地跟随彼此（感谢\[([^]]*)\]）。
答案 1 :(得分：1)
不需要任何花哨的东西，只需得到你需要的东西 替换回调。
未测试：
$new_input = preg_replace_callback('/(?i)\$[a-z]+\K(?:\[[^\[\]]*\])+/',
function( $matches ){
return preg_replace( '/(\[)|(\])/', "$1'$2", $matches[0]);
},
$input );