我正在为学校做一个简单的项目,但我被困住了。 我有一个我需要解决的bean FavoriteService。但是当我在我的servlet中自动装配bean时,我一直得到一个Null指针异常,我无法弄清楚原因。
FavoriteService
public class FavoriteService {
@Autowired
private Users users;
public boolean checkLogin(String username, String password) {
return users.login(username, password);
}
public void addUser(String rootUsername, String rootPassword, String username, String password)
{
if(rootUsername.equals("root") && rootPassword.equals("rootpasswd")) users.addUser(username, password);
}
public List<String> getFavorites(String username, String password)
{
List<String> favorites;
if(checkLogin(username, password))
{
favorites = users.getFavorites(username);
} else {
favorites = new ArrayList<String>();
}
return favorites;
}
public void addFavorite(String username, String password, String favorite)
{
if(checkLogin(username, password))
{
users.addFavorite(username, favorite);
}
}
public void removeFavorite(String username, String password, String favorite)
{
if(checkLogin(username, password))
{
users.removeFavorite(username, favorite);
}
}
}
的Servlet
public class LoginServlet extends HttpServlet {
@Autowired
private FavoriteService favoriteService;
@Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
String username = req.getParameter("username");
String password = req.getParameter("password");
System.out.println(favoriteService);
if(favoriteService.checkLogin(username, password))
{
resp.sendRedirect("root.jsp");
} else {
resp.sendRedirect("index.jsp");
}
}
}
springservlet-的servlet
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd">
<context:component-scan base-package="be.kdg.prog4.tdd"/>
<bean name="userDao" class="be.kdg.prog4.tdd.UserDaoWithMap" scope="singleton" />
<bean name="users" class="be.kdg.prog4.tdd.Users" scope="singleton" />
<bean name="favoriteService" class="be.kdg.prog4.tdd.FavoriteService" scope="singleton" />
<mvc:annotation-driven/>
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/"/>
<property name="suffix" value=".*"/>
</bean>
</beans>
Web.xml中
<web-app schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
version="2.5">
<display-name>TDD oefening</display-name>
<servlet>
<servlet-name>springservlet</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>springservlet</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>Login</servlet-name>
<servlet-class>be.kdg.prog4.tdd.LoginServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Login</servlet-name>
<url-pattern>/LoginServlet</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
如果您需要更多信息,请随时提出。 感谢。
编辑:
我在servlet init
中解决了这个问题 @Override
public void init(ServletConfig config) throws ServletException {
super.init(config);
SpringBeanAutowiringSupport.processInjectionBasedOnServletContext(this, config.getServletContext());
}
答案 0 :(得分:0)
如果你正在调用LoginServlet,那么你不会经历Spring。您直接在web.xml中映射它,并且set let容器正在初始化您的类而不通过Spring,并且自动装配不起作用。您需要通过springservlet的映射来访问服务器。
答案 1 :(得分:0)
Spring没有初始化Servlet,因此Spring没有初始化@Autowired
字段。
您可以覆盖Servlet @Autowired
方法并获取Spring Web上下文,并使用其init()
方法来获取您的bean。
getBean
。
这是你在init方法中获取Spring上下文的方法:
ctx = WebApplicationContextUtils.getWebApplicationContext(getServletContext());