Question

  import java.util.Scanner;
    public class Lab101{
        public static void main(String[]args){
        Scanner sc = new Scanner(System.in);  

     System.out.println("Enter Class Limit:");
     int x = sc.nextInt();

     for (char i=1; i<=x; i++) {
       System.out.println("Enter Student Name: ");
       sc.next().charAt(0);
     }

     System.out.println("Class Is Full");}}

Enter Class Limit:
3
Enter Student Name: 
Input
Enter Student Name: 
Name
Enter Student Name: 
Here
Class Is Full

我现在已经解决了我的问题。但后来我发现了一个新问题！

Enter Class Limit:
3
Enter Student Name: 
Input Name
Enter Student Name: 
Enter Student Name: 
Here
Class Is Full

一旦我进入了一个空间。它被计为一行中的两个输入并跳过第二行输入并前进到第三行。如何让它在一行中接受空间并将其计为一个，以便我可以像这样......

Enter Class Limit:
3
Enter Student Name: 
Input Name Here
Enter Student Name: 
Input Name Here
Enter Student Name: 
Input Name Here
Class Is Full

Answer 1

您不存储（或稍后显示）输入。我想你想做两件事。另外，如果您使用int阅读nextInt()，则必须使用nextLine()。您可以使用Arrays.toString(Object[])来显示学生姓名（所以String s）。像，

public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);

    System.out.println("Enter Class Limit:");
    int x = sc.nextInt();
    sc.nextLine(); // <-- there's a newline.
    String[] students = new String[x];
    for (int i = 0; i < x; i++) {
        System.out.printf("Enter Student Name %d: ", i + 1);
        System.out.flush();
        students[i] = sc.nextLine().trim();
    }

    System.out.println("Class Is Full");
    System.out.println(Arrays.toString(students));
}

我在JAVA循环时遇到问题

1 个答案: