我希望每个polymer-loader
的特定patch_no
与... champion
相同。 'Katarina'然后我想对Patches
与Created
列进行排序,Patch_No
列在不同的表格中,SELECT Patch_No
FROM champions , info
WHERE Champion = 'Katarina'
ORDER BY Created DESC
在表格之间连接。
info
示例ID Patch_No Created
165 1.0.0.126 2015-08-22 21:20:03
164 1.0.0.125 2015-08-22 21:03:40
163 1.0.0.124 2015-08-22 19:28:12
162 1.0.0.123 2015-08-22 19:03:59
161 1.0.0.122 2015-08-22 18:12:19
160 1.0.0.121 2015-08-22 17:30:26
159 1.0.0.120 2015-08-21 23:19:16
158 1.0.0.119 2015-08-21 22:13:31
157 1.0.0.118 2015-08-21 21:53:44
表:
champions
示例ID Patch_No Champion
66 1.0.0.32 Ashe
67 1.0.0.32 Cho’Gath
68 1.0.0.32 1-leimerdinger
69 1.0.0.32 Karthus
70 1.0.0.32 Katarina
71 1.0.0.32 Nunu
表:
%: foo += targ
x:
@echo $(foo)
答案 0 :(得分:1)
你做得很好,只需使用INNER Join即可获得理想的结果。您可以根据您想要输出数据的方式在Order by子句中使用ASC或DESC。
SELECT C.Patch_No
FROM champions C
INNER JOIN info I ON C.Patch_No = I.Patch_No
WHERE Champion = 'Katarina'
ORDER BY Created DESC
答案 1 :(得分:1)
您也可以使用此查询:
SELECT C.Patch_No
FROM champions C, info I
WHERE C.Patch_No = I.Patch_No
AND Champion = 'Katarina'
ORDER BY Created DESC
- )