使用PHP搜索多个列以获取json数据

时间:2015-08-22 19:52:17

标签: php json angularjs

以下代码可以通过filmName搜索电影,但我想添加更多功能,如搜索电影的年份和演员。由于我使用的是Angular JS,因此它很难实现

我的要求是使用更高级的搜索,例如filmbyyear和Actor Name,我可以使用上面的代码集成相同的代码,例如:

;WITH Points as( SELECT TOP 100 Name, AddressLine1, AddressLatitude, AddressLongitude , geography::STGeomFromText('POINT(' + CONVERT(varchar(50),AddressLatitude) + ' ' + CONVERT(varchar(50),AddressLongitude) + ')',4326) as GeoPoint FROM ServiceFacility WHERE 1=1 AND AddressLatitude BETWEEN -90 AND 90 AND AddressLongitude BETWEEN -90 AND 90) SELECT P1.*, CP.Name as DestinationName, CP.Dist INTO #tmp_Distance FROM Points P1 CROSS APPLY (SELECT Name, AlternateName, geography::STGeomFromText('POINT(' + CONVERT(varchar(50),P2.AddressLatitude) + ' ' + CONVERT(varchar(50),P2.AddressLongitude) + ')',4326).STDistance(P1.GeoPoint)/1609.344 as Dist FROM ServiceFacility as P2 WHERE 1=1 AND P1.Name <> P2.Name --Don't compare it to itself AND P2.AddressLatitude BETWEEN -90 AND 90 AND P2.AddressLongitude BETWEEN -90 AND 90 ) as CP CREATE CLUSTERED INDEX tmpIX ON #tmp_Distance (name, Dist) SELECT * FROM (SELECT *, ROW_NUMBER() OVER (PARTITION BY Name ORDER BY Dist ASC) as Rnk FROM #tmp_Distance) as tbl1 WHERE rnk = 1 DROP TABLE #tmp_Distance

搜索电影
filmName LIKE '%$filmName%' AND '%$filmYear%' AND '%$filmActor%'

1 个答案:

答案 0 :(得分:0)

根据您的数据,您需要对其进行解码

{"movie":[{"film":"Besharam","param":"besharam-film-2013.html","filmYear":"2013"‌​,"filmActor":"Ranbir Kapoor, Pallavi Sharda, Rishi Kapoor, Neetu Singh, Javed Jaffrey, Amitosh Nagpal, Kamal Kiri, Kunal Agrawal, Mohan Kapoor, Remo d'souza, Vishal Singh"}]}

$data = json_decode($json);
$file = $data->movie[0]->film;
$fileYear = $data->movie[0]->filmYear;