Question

所以我尝试从一个特定的界面以编程方式获取IP地址并将其显示在文本字段中。问题是它列出了几个。你如何迭代并获得双频无线-AC 3160的IP地址？

Dual Band Wireless-AC 3160 172.16.36.50
Dual Band Wireless-AC 3160 fe80:0:0:0:8877:2e6a:e4a1:c24f%wlan0
Virtual Ethernet Adapter for VMnet1 192.168.31.1
Virtual Ethernet Adapter for VMnet1 fe80:0:0:0:592c:71ac:f8d9:5899%eth3
Virtual Ethernet Adapter for VMnet8 192.168.245.1
Virtual Ethernet Adapter for VMnet8 fe80:0:0:0:ed34:4a7:cb5c:16ce%eth4

以下是我用来显示界面的代码：

String ip;
        try {
            Enumeration<NetworkInterface> interfaces = NetworkInterface.getNetworkInterfaces();
            int position;
            while (interfaces.hasMoreElements()) {
                NetworkInterface iface = interfaces.nextElement();
                //This filters out the interfaces
                // filters out 127.0.0.1 and inactive interfaces
                if (iface.isLoopback() || !iface.isUp())
                    continue;

                Enumeration<InetAddress> addresses = iface.getInetAddresses();
                while(addresses.hasMoreElements()) {
                    InetAddress addr = addresses.nextElement();
                    ip = addr.getHostAddress();

                    System.out.println(iface.getDisplayName() + " " + ip);
                }
            }
        } catch (SocketException e) {
            throw new RuntimeException(e);
        }

Answer 1

您将获得两个IP地址，因为该接口有两个IP地址。总的来说可能还会有更多。

如果您只想列出IPv4地址，可以检查地址是否为instanceof Inet4Address。

Answer 2

我通过以下方式解决了这个问题。谢谢。

String ip;

        try {
            Enumeration<NetworkInterface> interfaces = NetworkInterface.getNetworkInterfaces();
            int position =0;
            while (interfaces.hasMoreElements()) {
                NetworkInterface iface = interfaces.nextElement();
                //This filters out the interfaces
                // filters out 127.0.0.1 and inactive interfaces
                if (iface.isLoopback() || !iface.isUp())
                    continue;

                Enumeration<InetAddress> addresses = iface.getInetAddresses();
                while(addresses.hasMoreElements()) {
                    InetAddress addr = addresses.nextElement();
                    ip = addr.getHostAddress();
                    position++;

                    if (position == 0 ) {
                        System.out.println(iface.getDisplayName() + " " + ip);
                    }

                    else{
                        break;
                    }
                }
            }
        } catch (SocketException e) {
            throw new RuntimeException(e);
        }

Answer 3

使用此代码

import java.io.*;
import java.net.*;
import java.util.*;
import static java.lang.System.out;

public class ListNets {

    public static void main(String args[]) throws SocketException {
        Enumeration<NetworkInterface> nets = NetworkInterface.getNetworkInterfaces();
        for (NetworkInterface netint : Collections.list(nets))
            displayInterfaceInformation(netint);
    }

    static void displayInterfaceInformation(NetworkInterface netint) throws SocketException {
        out.printf("Display name: %s\n", netint.getDisplayName());
        out.printf("Name: %s\n", netint.getName());
        Enumeration<InetAddress> inetAddresses = netint.getInetAddresses();
        for (InetAddress inetAddress : Collections.list(inetAddresses)) {
            out.printf("InetAddress: %s\n", inetAddress);
        }
        out.printf("\n");
     }
}

如何显示特定界面的IP地址？

3 个答案: