Question

我正在尝试创建社交网络并在网站上添加通知栏，但代码未加载数据库中的数据。

$newpm_sql = mysql_query("SELECT * FROM `pm` 
                          WHERE `to` = '". $_SESSION['id'] ."' 
                          ORDER BY `id` DESC") or die(mysql_error());

if (mysql_num_rows($newpm_sql) == 0) { 
    $newpm = '<div id="notificationTitle">Meddelande</div>
    <div id="notificationsBody" class="notifications">
       Du har inga meddelanden! 
    </div>
'; 
} else {

    while ( $newpm = mysql_fetch_array( $newpm_sql )) {

        $from_sql = mysql_query("SELECT * FROM `members` 
                                 WHERE `id` = '". $newpm['from'] ."'") 
               or die(mysql_error());
        $from = mysql_fetch_array($from_sql);

        if ($newpm['status'] == 0) { 
            $newpm = '<div id="notificationTitle">Meddelande</div>
                      <div id="notificationsBody" notifications">'. 
                         $newpm['subject'] .' '. $newpm['from'] .
                       '</div>'; 
        }
    }
}

Answer 1

您正在使用变量field.SetValue(someObject, someValue);几乎所有内容，因此会破坏其中所持有的内容。

在第二个查询中使用新变量，我在下面使用$newpm作为示例

$row

此外，您不应该使用$newpm_sql = mysql_query("SELECT * FROM `pm` WHERE `to` = '". $_SESSION['id'] ."' ORDER BY `id` DESC") or die(mysql_error()); if (mysql_num_rows($newpm_sql) == 0) { $newpm = '<div id="notificationTitle">Meddelande</div> <div id="notificationsBody" class="notifications">Du har inga</div>'; } else { while ( $row = mysql_fetch_array( $newpm_sql )) { $from_sql = mysql_query("SELECT * FROM `members` WHERE `id` = '". $newpm_sql['from'] ."'") or die(mysql_error()); $from = mysql_fetch_array($from_sql); if ($row['status'] == 0) { $newpm = '<div id="notificationTitle">Meddelande</div> <div id="notificationsBody" notifications">'. $row['subject'] .' '. $row['from'] . '</div>'; } } }数据库访问扩展，它已被弃用，即将被删除。在您明显学习的过程中，请花时间学习mysql_扩展程序或mysqli_扩展程序。请参阅此方法以获取一些帮助，以确定您更喜欢Why shouldn't I use mysql_* functions in PHP?

我的MYSQL的信息没有显示？

1 个答案: