Question

我将控制器中的值传递给视图，地图中的值为：

    [title:[Feedback, Feedback, Suspension, Suspension],
     description:[Warning Letter, Warning Letter, Suspended, Suspended], 
     remark:[Testing, Testing Purpose, Bikrame, Nothing Serious], 
     date:[2015-08-12 00:00:00.0, 2015-08-19 00:00:00.0, 2015-08-22 00:00:00.0, 2015-08-25 00:00:00.0], 
     semesterNo:[2, 2, 2, 3]]

因为我试图使用gsp中的键来访问地图

    <g:each in="${awardsList}" var="values" status="i">
            ${values.getAt("title")}
    </g:each>

我收到错误

No such property: title for class: java.util.LinkedHashMap$Entry.Stacktrace follows:
Message: Error evaluating expression [values.getAt("title")] on line [91]:
No such property: title for class: java.util.LinkedHashMap$Entry

Answer 1

如果你的控制器返回一个地图数组作为你的awardsList：

，生活可能会更简单

[[title:'Feedback', description:'Warning Letter', remark:'Testing', date:'2015-08-12 00:00:00.0',semesterNo:2],
 [title:'Feedback',description:'Warning Letter', remark:'Testing Purpose', date:'2015-08-19 00:00:00.0', semesterNo:2],
 [title:'Suspension',description:'Suspended', remark:'Bikrame', date:'2015-08-22 00:00:00.0', semesterNo:2],
 [title:'Suspension',description:'Suspended', remark:'Nothing Serious',date:'2015-08-25 00:00:00.0',semesterNo:3]
]

然后：

<g:each in="${awardsList}" var="award">
    ${award.title}
</g:each>

Answer 2

g：每个块中的值是Map.Entry的实例，而不是 Map 。看起来您试图遍历 Map 的列表，而是通过单个 Map 进行交互。

您可以通过将控制器返回值放在列表中来解决此问题：

[
  [title:[Feedback, Feedback, Suspension, Suspension],
     description:[Warning Letter, Warning Letter, Suspended, Suspended], 
     remark:[Testing, Testing Purpose, Bikrame, Nothing Serious], 
     date:[2015-08-12 00:00:00.0, 2015-08-19 00:00:00.0, 2015-08-22 00:00:00.0, 2015-08-25 00:00:00.0], 
     semesterNo:[2, 2, 2, 3]]
]

如何在grails视图（gsp）中迭代Map？

2 个答案: