Question

我创建了一个bootstrap表单，并希望将表单中的数据包含到我的数据库中。我的问题是它不起作用，我不明白为什么。在我看来一切都是正确的。我现在正在寻找几个小时，但我无法找到问题。

您可以在此处找到我的表单：http://schulkantine.ccsolution.at/registration.php 请不要看风格，我必须稍后再定制。

这是我的register.php！数据库连接正在运行。

<?php
// Create connection credentials
$db_host = 'localhost';
$db_name = 'DBNAME';
$db_user = 'DBUSER';
$db_pass = 'DBPASSWORD';

// Create mysqli object
$connect = new mysqli ($db_host, $db_user, $db_pass, $db_name);

// Error Handler
if ($connect->connect_error) {
    printf ("Connection failed: %s\n", $connect->connect_error);
    exit();
}   
?>

<?php
// Check if form is submitted
if (isset ($_POST['submit'])) {
    $anrede = mysqli_real_escape_string ($connect, $_POST['anrede']);
    $vorname = mysqli_real_escape_string ($connect, $_POST['vorname']);
    $nachname = mysqli_real_escape_string ($connect, $_POST['nachname']);
    $strasse = mysqli_real_escape_string ($connect, $_POST['strasse']);
    $plz = mysqli_real_escape_string ($connect, $_POST['plz']);
    $ort = mysqli_real_escape_string ($connect, $_POST['ort']);
    $email = mysqli_real_escape_string ($connect, $_POST['email']);
    $telefon = mysqli_real_escape_string ($connect, $_POST['telefon']);

    // Validate Input
$query = mysql_query("INSERT INTO user (anrede, firstname_parent, lastname_parent, street_parent, plz_parent, city_parent, email, phonenumber_parent)
VALUES ('$anrede', '$vorname', '$nachname', '$strasse', '$plz', '$ort', '$email', '$telefon')") or die(mysql_error()); 
    }
    ?>

希望有人可以帮助我并告诉我我的错误是什么！

Answer 1

尝试更改

INSERT INTO user (anrede, firstname_parent, lastname_parent, street_parent, plz_parent, city_parent, email, phonenumber_parent) VALUES ('$anrede', '$vorname', '$nachname', '$strasse', '$plz', '$ort', '$email', '$telefon')"

到

INSERT INTO `user` (`anrede`, `firstname_parent`, `lastname_parent`, `street_parent`, `plz_parent`, `city_parent`, `email`, `phonenumber_parent`) VALUES ('$anrede', '$vorname', '$nachname', '$strasse', '$plz', '$ort', '$email', '$telefon')"

Answer 2

在registration.php文件中替换此行。你忘了添加＆＃34; name＆＃34;属性所以你的条件 if（isset（$ _POST [＆＃39; submit＆＃39;]））不起作用。

   <button type="submit" name="submit" value="submit" class="btn btn-custom pull-right">Send</button>

Bootstrap表单到数据库

2 个答案: