如何使用分裂字符串函数的结果与Angular.js一起订购？

Question

我正在显示一个示例员工数据表，我需要命令以姓氏命名。数据通过.JSON文件提供，名称只有一个字符串：

users.json

{
  "id": 5,
  "name": "Bob Smith",
  "username": "Eloyn.Skilles",
  "email": "smith.bob@bolly.biz",
  "address": {
    "street": "Rox Trial",
    "suite": "Suite 2890",
    "city": "Smashmouth",
    "zipcode": "58604­1099",
    "geo": {
      "lat": "27.8718",
      "lng": "21.8984"
    }
  },
  "phone": "210.067.6132",
  "website": "elvis.io",
  "company": {
    "name": "Johns Group",
    "catchPhrase": "Configurable multimedia task­force",
    "bs": "generate enterprise e­tailers"
  }
}

到目前为止，我已经能够将字符串分成两部分：

MainController.js

/* Function to split strings where there is a space present */
$scope.nameSplitter = function(string, index) {
    $scope.array = string.split(' ');
    return $scope.result = $scope.array[index];
}

这是HTML：

<table class="table table-striped table-bordered table-condensed table-hover">
    <th>Name</th>
    <th>Email</th>
    <th>Phone</th>

    <!-- Would like to ideally orderBy last name -->
    <tr ng-repeat="user in userData | orderBy:'name'">
        <td>{{ nameSplitter(user.name,1) }}, {{ nameSplitter(user.name,0) }}</td> <!--0 returns first name, 1 returns last name-->
        <td><a ng-href="mailto:{{user.email}}" target="_blank">{{user.email}}</a></td>
        <td><a ng-if="user.phone !== ''" href="tel:{{nameSplitter(user.phone, 0)}}" data-toggle="tooltip" title="{{nameSplitter(user.phone, 0)}}">
            <span class="glyphicon glyphicon-earphone"></span></a></td>
</table>

我尝试使用各种支架组合orderBy:'nameSplitter(user.name, 1)'，但没有运气。

Answer 1

orderBy也接受函数。

ng-repeat="user in userData | orderBy:getlastname" 

 $scope.getlastname = function(user) {
    var name =  user.name.split(' ');
    return name[1];
}

Answer 2

您可以在Array Angular orderBy docs

中使用function，attribute name或orderBy

所以在html中

<tr ng-repeat="user in userData | orderBy:myCustomOrderBy">

并在控制器中

$scope.myCustomOrderBy = function(user){
    return user.name.split(' '); //what you intent to here play on your own
}

范围内的当前用户作为参数传递

Answer 3

orderBy with a string是一个表达式，所以你可以包含函数，或者自定义函数可以作为参数而不是字符串提供。

<tr ng-repeat="user in userData | orderBy:'name.split(\' \')[1]'">