Question

我有一张这样的桌子;

CREATE TABLE [dbo].[TH_ORGANIZATION]
(
    [ID_CORGANIZATION] [decimal](18, 0) IDENTITY(1,1) NOT NULL,
    [ID_CCOMPANY] [nvarchar](10) NOT NULL,
    [CORGANIZATION_NAME_tr] [nvarchar](100) NULL,
    [CORGANIZATION_NAME_en] [nvarchar](100) NULL,
    [CORGANIZATION_MAN_ID_CEMP] [decimal](10, 0) NULL,
    [CORGANIZATION_UPLINK_ID] [decimal](18, 0) NULL,
    [CACTIVE] [bit] NOT NULL CONSTRAINT [DF_TH_ORGANIZATION_CACTIVE]  DEFAULT ((1)),

    CONSTRAINT [PK_TH_ORGANIZATION] 
       PRIMARY KEY CLUSTERED ([ID_CORGANIZATION] ASC)
           WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF,  
                 IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, 
                 ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
GO

现在我想写一个SQL查询来获取我的组织树。主列为ID_CORGANIZATION，子组织与CORGANIZATION_UPLINK_ID列相关联，表格相同。

有什么想法吗？

现在最好的解决方案是

 WITH temp as(SELECT * FROM TH_ORGANIZATION WHERE ID_CORGANIZATION = '3'  UNION ALL SELECT ei.* FROM TH_ORGANIZATION ei INNER JOIN temp x ON ei.CORGANIZATION_UPLINK_ID = x.ID_CORGANIZATION ") SELECT * FROM temp

Answer 1

SELECT * FROM TH_ORGANIZATION As O,
    TH_ORGANIZATION As Sub
WHERE O.ID_CORGANIZATION 
    = Sub.CORGANIZATION_UPLINK_ID;

您将获得一个包含其子组织的组织列表，递归。当然，您也可以订购列表。

如果您希望所有人都在一列之下，您可以像这样使用外部联接（因此只选择O。*）：

SELECT O.* FROM th_organization As O
LEFT OUTER JOIN th_organization As Sub
ON O.id_corganization 
    = Sub.corganization_uplink_id;

示例（我使用缩写），您应该得到这种列表：

id_c uplink_id  name
  1             OrgA
  2             OrgB 
 11      1      subA
 12      1      subB
 21      2      sub2
111     11      subsubA

Answer 2

我找到的最佳解决方案：

WITH temp as(SELECT * FROM TH_ORGANIZATION WHERE ID_CORGANIZATION = '3'  UNION ALL SELECT ei.* FROM TH_ORGANIZATION ei INNER JOIN temp x ON ei.CORGANIZATION_UPLINK_ID = x.ID_CORGANIZATION ") SELECT * FROM temp

注意：＆＃39; 3＆＃39;我刚开始的组织ID

SQL为组织树选择查询（层次结构）

2 个答案: