Question

我正在尝试执行插入操作，但是我收到的数字错误无效。我知道在哪里，但我不知道为什么或如何解决这个问题。一切都很好（我猜）。

以下是PL / SQL块：

DECLARE
  L_J_ID NUMBER := J_SEQ.NEXTVAL;
BEGIN

  INSERT INTO some_table
    (J_ID, E_TABLE_COLUMN, F_TABLE_COLUMN)
  VALUES
    (L_J_ID, 'a', 'b');

  INSERT INTO CFG_FILTER_JOIN
    (J_ID, E_TABLE_COLUMN, F_TABLE_COLUMN)
  VALUES
    (L_J_ID, 'c', 'd');
END;
/

DECLARE 
   var NUMBER;
BEGIN
  SELECT ID --number
    INTO var
    FROM some_table
   WHERE F_TABLE_COLUMN = 'a'
     AND E_TABLE_COLUMN = 'b';

  INSERT INTO my_table
    (ID, --in table definition: number(8)
     NAME, --varchar2(30)
     TYPE, --varchar2(30)
     TABLE_name, --varchar2(30)
     J_ID,  --number(8) --here is where I get the invalid number
     COLUMN,  --varchar2(30)
     COLUMN_TYPE, --varchar2(1)
     FILTER_LIST_ID) --number(8)
  VALUES
    (SEQ.NEXTVAL,
     'COL_LIST',
     'JL',
     var,  --here is where I get the invalid number
     'NB_CTL',
     'DEST',
     'V',
     4);
END;
/

怎么了？

Answer 1

将insert语句重写为伪代码：

INSERT INTO my_table
  (ID             = SEQ.NEXTVAL,
   NAME           = 'COL_LIST',
   TYPE           = 'JL',
   TABLE          = var,
   J_ID           = 'NB_CTL',
   COLUMN         = 'DEST',
   COLUMN_TYPE    = 'V',
   FILTER_LIST_ID = 4)

为数字J_ID列分配字符串值＆＃39; NB_CTL＆＃39;。

Answer 2

Table是双引号（“table”）中的保留关键字括起来的表。并且发生了列不匹配。通过重写你的plsql块是

    DECLARE
          L_J_ID NUMBER := J_SEQ.NEXTVAL;
        BEGIN

          INSERT INTO some_table
            (J_ID, E_TABLE_COLUMN, F_TABLE_COLUMN)
          VALUES
            (L_J_ID, 'a', 'b');

          INSERT INTO CFG_FILTER_JOIN
            (J_ID, E_TABLE_COLUMN, F_TABLE_COLUMN)
          VALUES
            (L_J_ID, 'c', 'd');
        END;
        /

        DECLARE 
           var NUMBER;
        BEGIN
          SELECT ID --number
            INTO var
            FROM some_table
           WHERE F_TABLE_COLUMN = 'a'
             AND E_TABLE_COLUMN = 'b';

          INSERT INTO my_table
            (ID, --in table definition: number(8)
             NAME, --varchar2(30)
             TYPE, --varchar2(30)
             j_id  --number(8)
              "TABLE", --varchar2(30)--here is where I get the invalid number
             COLUMN,  --varchar2(30)
             COLUMN_TYPE, --varchar2(1)
             FILTER_LIST_ID) --number(8)
          VALUES
            (SEQ.NEXTVAL,
           'COL_LIST',
            'JL',
             var,
            'NB_CTL',
             'DEST',
             'V',
              4);

        END;

保留关键字为：http://docs.oracle.com/cd/B19306_01/em.102/b40103/app_oracle_reserved_words.htm

Ora-01722号码无效

2 个答案: