Question

我想知道如何检查这个。例如：

var products = [
    {
        title: 'Product 1',
        categories: ['One', 'Two', 'Three']
    },
    {
        title: 'Product 2',
        categories: ['Three', 'Four']
    }
];

var categories = ['Two','Four'];

如何让两种产品与其中一种产品相匹配？希望有人可以帮助我:)）

Answer 1

plain js：

products.filter(function(product) {
  return categories.some(function(cat) {
     return product.categories.indexOf(cat) >= 0;
  });
});

lodash：

_.filter(products, function(product) {
  return _.some(categories, function(cat) {
     return _.indexOf(product.categories, cat) >= 0;
  });
});

Answer 2

使用简单的for：

var products = [
    {
        title: 'Product 1',
        categories: ['One', 'Two', 'Three']
    },
    {
        title: 'Product 2',
        categories: ['Three', 'Four']
    }
];

var categories = ['Two', 'Four'];

var list = []
for (x in products) {
    for (y in products[x].categories) {
        if (categories.indexOf(products[x].categories[y]) != -1) {
            list.push(products[x].title)
        }
    }
}

console.log(list) //here your match

Answer 3

从代码方面来说不是很好的解决方案，但它可以很明确（如果有人不理解）并且它的工作

＆＃13;

var products = [
    {
        title: 'Product 1',
        categories: ['One', 'Two', 'Three']
    },
    {
        title: 'Product 2',
        categories: ['Three', 'Four']
    }
];

var categories = ['Two','Four'];
var retArr = [];


for (i = 0; i < categories.length; ++i) {
 	for (j = 0; j < products.length; ++j) {
    	if(products[j].categories.indexOf(categories[i]) > -1){ // check if product categories contains some category. If yes, then add to array
            retArr.push(products[j]);
        }
    }
}

console.log(retArr);

＆＃13;

Answer 4

简单地循环：

var foundproducts = [];
for (i = 0; i < products.length; i++) {
    for (u = 0; u < categories.length; u++) { 
        if (products[i].categories.indexOf(categories[u]) != -1) { 
            foundproducts.push(products[i].title);
            break;
        } 
    }
}

JavaScript Array indexOf数组？

4 个答案:

plain js：

lodash：