Swift:想要将Array添加到现有词典

时间:2015-08-21 11:04:46

标签: ios swift dictionary

拥有包含所有会话的JSON对象,以及包含来自特定会话的所有消息的JSON对象。解析这些JSON对象并将值放在Dictionary中,然后放入Array中。到目前为止,这很好,这可以按预期工作。

func didReceiveConversations(result: JSON) {
    var conversationsArray = [AnyObject]()

    for (key: String, subJson: JSON) in result["Data"] {
        var conversationDictionary = [String: AnyObject]()
        conversationDictionary["DeviceOnline"] = subJson["DeviceOnline"].boolValue
        conversationDictionary["Id"] = subJson["Id"].stringValue

        self.conversationsArray.append(conversationDictionary)
    }
}

conversationationsArray填写如下:

[{
    Id = "94cc96b5-d063-41a0-ae03-6d1a868836fb";
    DeviceOnline = 1;
}, {
    Id = "4b321903-af6a-405d-ac4f-c0799a7f714a";
    DeviceOnline = 1;
}]

然后我创建一个messagesArray,其中包含一个值为:

的Dictionary
func didReceiveResultSpecificConversation(result: JSON) {
    var messagesArray = [AnyObject]()

    for (key: String, subJson: JSON) in result {
        var messageDictionary = [String: AnyObject]()

        messageDictionary["MessageId"] = subJson["MessageId"].stringValue
        messageDictionary["MessageText"] = subJson["MessageText"].stringValue

        messagesArray.append(messageDictionary)
    }

    // I guess here comes the code to add the messages to the conversationsArray 
    // in the Dictionary under a key: "Messages" for example so I tried this: 
    for conversation in self.conversationsArray {
        if conversation["Id"] as! String == messagesArray[0]["ConversationId"] as! String {
           conversation["Messages"] = messagesArray as [String: AnyObject]
        }
    }
    // This gives me: Cannot assign a value of type '[String: AnyObject]' to 
    // a value of type 'AnyObject?!'


     messagesArray.removeAll(keepCapacity: false)
}

我认为现在将messagesArray添加到conversationsArray(通过创建新密钥:“Messages”,并使用messagesArray填充值)非常简单,但我似乎无法让它工作。我已经尝试过for循环来完成对话,但是我一直在弄错类型和东西。

conversationsArray的最终结果应该是这样的:

[{
    Id = "94cc96b5-d063-41a0-ae03-6d1a868836fb";
    DeviceOnline = 1;
    Messages [{
        MessageId = "1"
        MessageText = "Foo"
    },{
        MessageId = "2"
        MessageText = "Bar"
    }]
}, {
    Id = "4b321903-af6a-405d-ac4f-c0799a7f714a";
    DeviceOnline = 1;
    Messages [{
        MessageId = "1"
        MessageText = "Hello"
    },{
        MessageId = "2"
        MessageText = "World"
    }]
}]

有人能指出我正确的方向,因为我必须在这里找到一些非常简单的东西。谢谢!

2 个答案:

答案 0 :(得分:1)

由于您知道所有字典键都是String,因此将两个数组定义为更具体的类型

 [Dictionary<String,AnyObject>]()

答案 1 :(得分:0)

我在这里寻求最简单的解释,但如果你得到错误:
mongo::BSONObj* curr_elem=new mongo::BSONObj(); (*curr_elem)=cursor->next().getOwned(); //or: next().copy();

不会尝试将数组转换为AnyObject工作吗?

Cannot assign a value of type '[String: AnyObject]' to a value of type AnyObject