Question

错误是：您没有选择要上传的文件。

我的控制器：

        $image_name=$_FILES['screen_img']['name'];
        $config['upload_path']=FCPATH.'asset/project_images/';
        $config['allowed_types']='jpeg|jpg|png';
        $config['overwrite']=true;
        $config['max_size']="2048000";
        $config['file_name']=$image_name;
        $config['max_height']="768";
        $config['max_width']="1024";
        $this->load->library('upload');
        $this->upload->initialize($config);
        if(!$this->upload->do_upload($image_name))
        {
         $error = array('error' => $this->upload->display_errors());
         print_r($error);
         $this->load->view('screen/new_screen', $error);
        }
        else
        {
            $data = array('upload_data' => $this->upload->data());
             print_r($data);
            $this->load->view('screen/new_screen',$data);
        }

我的观点

<?php  echo  form_open_multipart('screen/new_screen')?>
<input type="file" class="form-control"  name="screen_img" /><br>
<input type="submit"  class="btn btn-success" name="submit" value="submit">
<?php  echo form_close();?>

我尝试了所有互联网的例子，但它们没有用。我找不到问题。

Answer 1

您需要在do_upload函数中编写字段名称

SELECT 
  id 
FROM relationships a
WHERE 
  a.term_id = 5 AND 
  EXISTS (SELECT * FROM relationships b WHERE b.term_id = 8 AND b.id = a.id) > 0

而不是if(!$this->upload->do_upload("screen_img"))

无法在codeigniter中上传图片？

1 个答案: