是否有一种将整数转换为书写数字的有效方法，例如：
string Written = IntegerToWritten(21);
将返回“Twenty One”。
有没有办法做到这一点，不涉及大量的查询表？
答案 0 :(得分：63)
这应该合理地运作：
public static class HumanFriendlyInteger
{
static string[] ones = new string[] { "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" };
static string[] teens = new string[] { "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" };
static string[] tens = new string[] { "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };
static string[] thousandsGroups = { "", " Thousand", " Million", " Billion" };
private static string FriendlyInteger(int n, string leftDigits, int thousands)
{
if (n == 0)
{
return leftDigits;
}
string friendlyInt = leftDigits;
if (friendlyInt.Length > 0)
{
friendlyInt += " ";
}
if (n < 10)
{
friendlyInt += ones[n];
}
else if (n < 20)
{
friendlyInt += teens[n - 10];
}
else if (n < 100)
{
friendlyInt += FriendlyInteger(n % 10, tens[n / 10 - 2], 0);
}
else if (n < 1000)
{
friendlyInt += FriendlyInteger(n % 100, (ones[n / 100] + " Hundred"), 0);
}
else
{
friendlyInt += FriendlyInteger(n % 1000, FriendlyInteger(n / 1000, "", thousands+1), 0);
if (n % 1000 == 0)
{
return friendlyInt;
}
}
return friendlyInt + thousandsGroups[thousands];
}
public static string IntegerToWritten(int n)
{
if (n == 0)
{
return "Zero";
}
else if (n < 0)
{
return "Negative " + IntegerToWritten(-n);
}
return FriendlyInteger(n, "", 0);
}
}
（编辑修复一个百万，十亿等错误）
答案 1 :(得分：13)
我使用这个名为Humanizer的方便库。
https://github.com/Humanizr/Humanizer
它支持多种文化，不仅可以将数字转换为单词，还可以转换为日期，并且使用起来非常简单。
以下是我如何使用它：
int someNumber = 543;
var culture = System.Globalization.CultureInfo("en-US");
var result = someNumber.ToWords(culture); // 543 -> five hundred forty-three
瞧！
答案 2 :(得分：7)
我使用此代码。它是VB代码，但您可以轻松地将其转换为C＃。它的工作原理
Function NumberToText(ByVal n As Integer) As String
Select Case n
Case 0
Return ""
Case 1 To 19
Dim arr() As String = {"One","Two","Three","Four","Five","Six","Seven", _
"Eight","Nine","Ten","Eleven","Twelve","Thirteen","Fourteen", _
"Fifteen","Sixteen","Seventeen","Eighteen","Nineteen"}
Return arr(n-1) & " "
Case 20 to 99
Dim arr() as String = {"Twenty","Thirty","Forty","Fifty","Sixty","Seventy","Eighty","Ninety"}
Return arr(n\10 -2) & " " & NumberToText(n Mod 10)
Case 100 to 199
Return "One Hundred " & NumberToText(n Mod 100)
Case 200 to 999
Return NumberToText(n\100) & "Hundreds " & NumberToText(n mod 100)
Case 1000 to 1999
Return "One Thousand " & NumberToText(n Mod 1000)
Case 2000 to 999999
Return NumberToText(n\1000) & "Thousands " & NumberToText(n Mod 1000)
Case 1000000 to 1999999
Return "One Million " & NumberToText(n Mod 1000000)
Case 1000000 to 999999999
Return NumberToText(n\1000000) & "Millions " & NumberToText(n Mod 1000000)
Case 1000000000 to 1999999999
Return "One Billion " & NumberTotext(n Mod 1000000000)
Case Else
Return NumberToText(n\1000000000) & "Billion " _
& NumberToText(n mod 1000000000)
End Select
End Function
以下是c＃
中的代码public static string AmountInWords(double amount)
{
var n = (int)amount;
if (n == 0)
return "";
else if (n > 0 && n <= 19)
{
var arr = new string[] { "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" };
return arr[n - 1] + " ";
}
else if (n >= 20 && n <= 99)
{
var arr = new string[] { "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };
return arr[n / 10 - 2] + " " + AmountInWords(n % 10);
}
else if (n >= 100 && n <= 199)
{
return "One Hundred " + AmountInWords(n % 100);
}
else if (n >= 200 && n <= 999)
{
return AmountInWords(n / 100) + "Hundred " + AmountInWords(n % 100);
}
else if (n >= 1000 && n <= 1999)
{
return "One Thousand " + AmountInWords(n % 1000);
}
else if (n >= 2000 && n <= 999999)
{
return AmountInWords(n / 1000) + "Thousand " + AmountInWords(n % 1000);
}
else if (n >= 1000000 && n <= 1999999)
{
return "One Million " + AmountInWords(n % 1000000);
}
else if (n >= 1000000 && n <= 999999999)
{
return AmountInWords(n / 1000000) + "Million " + AmountInWords(n % 1000000);
}
else if (n >= 1000000000 && n <= 1999999999)
{
return "One Billion " + AmountInWords(n % 1000000000);
}
else
{
return AmountInWords(n / 1000000000) + "Billion " + AmountInWords(n % 1000000000);
}
}
答案 3 :(得分：4)
贾斯汀罗杰斯有一个“NumbersToEnglish”课程，应该很适合你！
首次发布。
http://weblogs.asp.net/justin_rogers/archive/2004/06/09/151675.aspx
最终源代码
http://weblogs.asp.net/justin_rogers/articles/151757.aspx
它确实有一些内部查找表，但我真的不知道你将如何摆脱它。
答案 4 :(得分：3)
为什么大量查找表？
string GetWrittenInteger(int n)
{
string[] a = new string[] {"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" }
string[] b = new string[] { "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" }
string[] c = new string[] {"Twenty", "Thirty", "Forty", "Sixty", "Seventy", "Eighty", "Ninety"};
string[] d = new string[] {"Hundred", "Thousand", "Million"}
string s = n.ToString();
for (int i = 0; i < s.Length; i++)
{
// logic (too lazy but you get the idea)
}
}
答案 5 :(得分：2)
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace tryingstartfror4digits
{
class Program
{
static void Main(string[] args)
{
Program pg = new Program();
Console.WriteLine("Enter ur number");
int num = Convert.ToInt32(Console.ReadLine());
if (num <= 19)
{
string g = pg.first(num);
Console.WriteLine("The number is " + g);
}
else if ((num >= 20) && (num <= 99))
{
if (num % 10 == 0)
{
string g = pg.second(num / 10);
Console.WriteLine("The number is " + g);
}
else
{
string g = pg.second(num / 10) + pg.first(num % 10);
Console.WriteLine("The number is " + g);
}
}
else if ((num >= 100) && (num <= 999))
{
int k = num % 100;
string g = pg.first(num / 100) +pg.third(0) + pg.second(k / 10)+pg.first(k%10);
Console.WriteLine("The number is " + g);
}
else if ((num >= 1000) && (num <= 19999))
{
int h = num % 1000;
int k = h % 100;
string g = pg.first(num / 1000) + "Thousand " + pg.first(h/ 100) + pg.third(k) + pg.second(k / 10) + pg.first(k % 10);
Console.WriteLine("The number is " + g);
}
Console.ReadLine();
}
public string first(int num)
{
string name;
if (num == 0)
{
name = " ";
}
else
{
string[] arr1 = new string[] { "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" , "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"};
name = arr1[num - 1];
}
return name;
}
public string second(int num)
{
string name;
if ((num == 0)||(num==1))
{
name = " ";
}
else
{
string[] arr1 = new string[] { "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };
name = arr1[num - 2];
}
return name;
}
public string third(int num)
{
string name ;
if (num == 0)
{
name = "";
}
else
{
string[] arr1 = new string[] { "Hundred" };
name = arr1[0];
}
return name;
}
}
}
这项工作正常，从1到19999将在我完成后立即更新
答案 6 :(得分：2)
接受的答案似乎并不完美。它没有处理像二十一这样的数字的破折号，它没有将“和”这个词放在像“一百零一”这样的数字中，而且，它是递归的。
以下是我对答案的看法。它智能地添加“和”字，并适当地连字。如果需要任何修改，请告诉我。
以下是如何调用它（显然你想将它放在某个类的某个类中）：
for (int i = int.MinValue+1; i < int.MaxValue; i++)
{
Console.WriteLine(ToWords(i));
}
以下是代码：
private static readonly string[] Ones = {"", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"};
private static readonly string[] Teens =
{
"Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen",
"Seventeen", "Eighteen", "Nineteen"
};
private static readonly string[] Tens =
{
"", "", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty",
"Ninety"
};
public static string ToWords(int number)
{
if (number == 0)
return "Zero";
var wordsList = new List<string>();
if (number < 0)
{
wordsList.Add("Negative");
number = Math.Abs(number);
}
if (number >= 1000000000 && number <= int.MaxValue) //billions
{
int billionsValue = number / 1000000000;
GetValuesUnder1000(billionsValue, wordsList);
wordsList.Add("Billion");
number -= billionsValue * 1000000000;
if (number > 0 && number < 10)
wordsList.Add("and");
}
if (number >= 1000000 && number < 1000000000) //millions
{
int millionsValue = number / 1000000;
GetValuesUnder1000(millionsValue, wordsList);
wordsList.Add("Million");
number -= millionsValue * 1000000;
if (number > 0 && number < 10)
wordsList.Add("and");
}
if (number >= 1000 && number < 1000000) //thousands
{
int thousandsValue = number/1000;
GetValuesUnder1000(thousandsValue, wordsList);
wordsList.Add("Thousand");
number -= thousandsValue * 1000;
if (number > 0 && number < 10)
wordsList.Add("and");
}
GetValuesUnder1000(number, wordsList);
return string.Join(" ", wordsList);
}
private static void GetValuesUnder1000(int number, List<string> wordsList)
{
while (number != 0)
{
if (number < 10)
{
wordsList.Add(Ones[number]);
number -= number;
}
else if (number < 20)
{
wordsList.Add(Teens[number - 10]);
number -= number;
}
else if (number < 100)
{
int tensValue = ((int) (number/10))*10;
int onesValue = number - tensValue;
if (onesValue == 0)
{
wordsList.Add(Tens[tensValue/10]);
}
else
{
wordsList.Add(Tens[tensValue/10] + "-" + Ones[onesValue]);
}
number -= tensValue;
number -= onesValue;
}
else if (number < 1000)
{
int hundredsValue = ((int) (number/100))*100;
wordsList.Add(Ones[hundredsValue/100]);
wordsList.Add("Hundred");
number -= hundredsValue;
if (number > 0)
wordsList.Add("and");
}
}
}
答案 7 :(得分：1)
这是一个C# Console Application，它将返回整数和小数。
答案 8 :(得分：1)
只需获取该字符串并转换为 像 string s = txtNumber.Text.Tostring（）; int i = Convert.ToInt32（s.Tostring（））; 它只会写出完整的整数值
答案 9 :(得分：1)
Nick Masao对孟加拉语Numeric同样问题的回答。数字的初始输入是Unicode字符串。干杯!!
string number = "২২৮৯";
number = number.Replace("০", "0").Replace("১", "1").Replace("২", "2").Replace("৩", "3").Replace("৪", "4").Replace("৫", "5").Replace("৬", "6").Replace("৭", "7").Replace("৮", "8").Replace("৯", "9");
double vtempdbl = Convert.ToDouble(number);
string amount = AmountInWords(vtempdbl);
private static string AmountInWords(double amount)
{
var n = (int)amount;
if (n == 0)
return " ";
else if (n > 0 && n <= 99)
{
var arr = new string[] { "এক", "দুই", "তিন", "চার", "পাঁচ", "ছয়", "সাত", "আট", "নয়", "দশ", "এগার", "বারো", "তের", "চৌদ্দ", "পনের", "ষোল", "সতের", "আঠার", "ঊনিশ", "বিশ", "একুশ", "বাইস", "তেইশ", "চব্বিশ", "পঁচিশ", "ছাব্বিশ", "সাতাশ", "আঠাশ", "ঊনত্রিশ", "ত্রিশ", "একত্রিস", "বত্রিশ", "তেত্রিশ", "চৌত্রিশ", "পঁয়ত্রিশ", "ছত্রিশ", "সাঁইত্রিশ", "আটত্রিশ", "ঊনচল্লিশ", "চল্লিশ", "একচল্লিশ", "বিয়াল্লিশ", "তেতাল্লিশ", "চুয়াল্লিশ", "পয়তাল্লিশ", "ছিচল্লিশ", "সাতচল্লিশ", "আতচল্লিশ", "উনপঞ্চাশ", "পঞ্চাশ", "একান্ন", "বায়ান্ন", "তিপ্পান্ন", "চুয়ান্ন", "পঞ্চান্ন", "ছাপ্পান্ন", "সাতান্ন", "আটান্ন", "উনষাট", "ষাট", "একষট্টি", "বাষট্টি", "তেষট্টি", "চৌষট্টি", "পয়ষট্টি", "ছিষট্টি", " সাতষট্টি", "আটষট্টি", "ঊনসত্তর ", "সত্তর", "একাত্তর ", "বাহাত্তর", "তেহাত্তর", "চুয়াত্তর", "পঁচাত্তর", "ছিয়াত্তর", "সাতাত্তর", "আটাত্তর", "ঊনাশি", "আশি", "একাশি", "বিরাশি", "তিরাশি", "চুরাশি", "পঁচাশি", "ছিয়াশি", "সাতাশি", "আটাশি", "উননব্বই", "নব্বই", "একানব্বই", "বিরানব্বই", "তিরানব্বই", "চুরানব্বই", "পঁচানব্বই ", "ছিয়ানব্বই ", "সাতানব্বই", "আটানব্বই", "নিরানব্বই" };
return arr[n - 1] + " ";
}
else if (n >= 100 && n <= 199)
{
return AmountInWords(n / 100) + "এক শত " + AmountInWords(n % 100);
}
else if (n >= 100 && n <= 999)
{
return AmountInWords(n / 100) + "শত " + AmountInWords(n % 100);
}
else if (n >= 1000 && n <= 1999)
{
return "এক হাজার " + AmountInWords(n % 1000);
}
else if (n >= 1000 && n <= 99999)
{
return AmountInWords(n / 1000) + "হাজার " + AmountInWords(n % 1000);
}
else if (n >= 100000 && n <= 199999)
{
return "এক লাখ " + AmountInWords(n % 100000);
}
else if (n >= 100000 && n <= 9999999)
{
return AmountInWords(n / 100000) + "লাখ " + AmountInWords(n % 100000);
}
else if (n >= 10000000 && n <= 19999999)
{
return "এক কোটি " + AmountInWords(n % 10000000);
}
else
{
return AmountInWords(n / 10000000) + "কোটি " + AmountInWords(n % 10000000);
}
}
答案 10 :(得分：1)
以下C＃控制台应用代码将接受最多2位小数的货币值，并以英文显示。这不仅将整数转换为英语等价物，还将其转换为美元和美分的货币价值。
namespace ConsoleApplication2
{
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;
class Program
{
static void Main(string[] args)
{
bool repeat = true;
while (repeat)
{
string inputMonetaryValueInNumberic = string.Empty;
string centPart = string.Empty;
string dollarPart = string.Empty;
Console.Write("\nEnter the monetary value : ");
inputMonetaryValueInNumberic = Console.ReadLine();
inputMonetaryValueInNumberic = inputMonetaryValueInNumberic.TrimStart('0');
if (ValidateInput(inputMonetaryValueInNumberic))
{
if (inputMonetaryValueInNumberic.Contains('.'))
{
centPart = ProcessCents(inputMonetaryValueInNumberic.Substring(inputMonetaryValueInNumberic.IndexOf(".") + 1));
dollarPart = ProcessDollar(inputMonetaryValueInNumberic.Substring(0, inputMonetaryValueInNumberic.IndexOf(".")));
}
else
{
dollarPart = ProcessDollar(inputMonetaryValueInNumberic);
}
centPart = string.IsNullOrWhiteSpace(centPart) ? string.Empty : " and " + centPart;
Console.WriteLine(string.Format("\n\n{0}{1}", dollarPart, centPart));
}
else
{
Console.WriteLine("Invalid Input..");
}
Console.WriteLine("\n\nPress any key to continue or Escape of close : ");
var loop = Console.ReadKey();
repeat = !loop.Key.ToString().Contains("Escape");
Console.Clear();
}
}
private static string ProcessCents(string cents)
{
string english = string.Empty;
string dig3 = Process3Digit(cents);
if (!string.IsNullOrWhiteSpace(dig3))
{
dig3 = string.Format("{0} {1}", dig3, GetSections(0));
}
english = dig3 + english;
return english;
}
private static string ProcessDollar(string dollar)
{
string english = string.Empty;
foreach (var item in Get3DigitList(dollar))
{
string dig3 = Process3Digit(item.Value);
if (!string.IsNullOrWhiteSpace(dig3))
{
dig3 = string.Format("{0} {1}", dig3, GetSections(item.Key));
}
english = dig3 + english;
}
return english;
}
private static string Process3Digit(string digit3)
{
string result = string.Empty;
if (Convert.ToInt32(digit3) != 0)
{
int place = 0;
Stack<string> monetaryValue = new Stack<string>();
for (int i = digit3.Length - 1; i >= 0; i--)
{
place += 1;
string stringValue = string.Empty;
switch (place)
{
case 1:
stringValue = GetOnes(digit3[i].ToString());
break;
case 2:
int tens = Convert.ToInt32(digit3[i]);
if (tens == 1)
{
if (monetaryValue.Count > 0)
{
monetaryValue.Pop();
}
stringValue = GetTens((digit3[i].ToString() + digit3[i + 1].ToString()));
}
else
{
stringValue = GetTens(digit3[i].ToString());
}
break;
case 3:
stringValue = GetOnes(digit3[i].ToString());
if (!string.IsNullOrWhiteSpace(stringValue))
{
string postFixWith = " Hundred";
if (monetaryValue.Count > 0)
{
postFixWith = postFixWith + " And";
}
stringValue += postFixWith;
}
break;
}
if (!string.IsNullOrWhiteSpace(stringValue))
monetaryValue.Push(stringValue);
}
while (monetaryValue.Count > 0)
{
result += " " + monetaryValue.Pop().ToString().Trim();
}
}
return result;
}
private static Dictionary<int, string> Get3DigitList(string monetaryValueInNumberic)
{
Dictionary<int, string> hundredsStack = new Dictionary<int, string>();
int counter = 0;
while (monetaryValueInNumberic.Length >= 3)
{
string digit3 = monetaryValueInNumberic.Substring(monetaryValueInNumberic.Length - 3, 3);
monetaryValueInNumberic = monetaryValueInNumberic.Substring(0, monetaryValueInNumberic.Length - 3);
hundredsStack.Add(++counter, digit3);
}
if (monetaryValueInNumberic.Length != 0)
hundredsStack.Add(++counter, monetaryValueInNumberic);
return hundredsStack;
}
private static string GetTens(string tensPlaceValue)
{
string englishEquvalent = string.Empty;
int value = Convert.ToInt32(tensPlaceValue);
Dictionary<int, string> tens = new Dictionary<int, string>();
tens.Add(2, "Twenty");
tens.Add(3, "Thirty");
tens.Add(4, "Forty");
tens.Add(5, "Fifty");
tens.Add(6, "Sixty");
tens.Add(7, "Seventy");
tens.Add(8, "Eighty");
tens.Add(9, "Ninty");
tens.Add(10, "Ten");
tens.Add(11, "Eleven");
tens.Add(12, "Twelve");
tens.Add(13, "Thrteen");
tens.Add(14, "Fourteen");
tens.Add(15, "Fifteen");
tens.Add(16, "Sixteen");
tens.Add(17, "Seventeen");
tens.Add(18, "Eighteen");
tens.Add(19, "Ninteen");
if (tens.ContainsKey(value))
{
englishEquvalent = tens[value];
}
return englishEquvalent;
}
private static string GetOnes(string onesPlaceValue)
{
int value = Convert.ToInt32(onesPlaceValue);
string englishEquvalent = string.Empty;
Dictionary<int, string> ones = new Dictionary<int, string>();
ones.Add(1, " One");
ones.Add(2, " Two");
ones.Add(3, " Three");
ones.Add(4, " Four");
ones.Add(5, " Five");
ones.Add(6, " Six");
ones.Add(7, " Seven");
ones.Add(8, " Eight");
ones.Add(9, " Nine");
if (ones.ContainsKey(value))
{
englishEquvalent = ones[value];
}
return englishEquvalent;
}
private static string GetSections(int section)
{
string sectionName = string.Empty;
switch (section)
{
case 0:
sectionName = "Cents";
break;
case 1:
sectionName = "Dollars";
break;
case 2:
sectionName = "Thousand";
break;
case 3:
sectionName = "Million";
break;
case 4:
sectionName = "Billion";
break;
case 5:
sectionName = "Trillion";
break;
case 6:
sectionName = "Zillion";
break;
}
return sectionName;
}
private static bool ValidateInput(string input)
{
return Regex.IsMatch(input, "[0-9]{1,18}(\\.[0-9]{1,2})?"))
}
}
}
答案 11 :(得分：0)
仅供土耳其人代表HumanFriendlyInteger（↑）（Türkçe，sayıyazıkarşılığı）：
public static class HumanFriendlyInteger
{
static string[] ones = new string[] { "", "Bir", "İki", "Üç", "Dört", "Beş", "Altı", "Yedi", "Sekiz", "Dokuz" };
static string[] teens = new string[] { "On", "On Bir", "On İki", "On Üç", "On Dört", "On Beş", "On Altı", "On Yedi", "On Sekiz", "On Dokuz" };
static string[] tens = new string[] { "Yirmi", "Otuz", "Kırk", "Elli", "Altmış", "Yetmiş", "Seksen", "Doksan" };
static string[] thousandsGroups = { "", " Bin", " Milyon", " Milyar" };
private static string FriendlyInteger(int n, string leftDigits, int thousands)
{
if (n == 0)
{
return leftDigits;
}
string friendlyInt = leftDigits;
if (friendlyInt.Length > 0)
{
friendlyInt += " ";
}
if (n < 10)
friendlyInt += ones[n];
else if (n < 20)
friendlyInt += teens[n - 10];
else if (n < 100)
friendlyInt += FriendlyInteger(n % 10, tens[n / 10 - 2], 0);
else if (n < 1000)
friendlyInt += FriendlyInteger(n % 100, ((n / 100 == 1 ? "" : ones[n / 100] + " ") + "Yüz"), 0); // Yüz 1 ile başlangıçta "Bir" kelimesini Türkçe'de almaz.
else
friendlyInt += FriendlyInteger(n % 1000, FriendlyInteger(n / 1000, "", thousands + 1), 0);
return friendlyInt + thousandsGroups[thousands];
}
public static string IntegerToWritten(int n)
{
if (n == 0)
return "Sıfır";
else if (n < 0)
return "Eksi " + IntegerToWritten(-n);
return FriendlyInteger(n, "", 0);
}