Question

我声明我在Mac OSX上使用Hibernate，MySQL。

我看了关注我的问题的帖子，但不幸的是我无法解决它。下面是有问题的代码：

public List<FeedMessage> getLatestFeedMessage() {
    List<FeedMessage> messages = new ArrayList<>();

    String hql = "from (select nomeFeed, title, max(pubDate) as maxdate "
                  + "from FeedMessage group by nomeFeed) as x inner join FeedMessage as f "
                                    + "on f.nomeFeed = x.nomeFeed and f.pubDate = x.maxdate";


    System.out.println(hql);
    try {
        session = HibernateUtil.getSessionFactory().openSession();
        Query query = session.createQuery(hql);
        messages=query.list();
    } catch (QueryException e) {
        e.printStackTrace();
    } finally {
        if(session.isOpen())
        session.close();
    }

    return messages;

}

我试图从MySQL数据库中选择每个组的第一行，但是我收到以下错误：

org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: ( near line 1, column 6 [from (select nomeFeed, title, max(pubDate) as maxdate from it.unirc.fantapjam.FeedMessage.Model.FeedMessage group by nomeFeed) as x inner join FeedMessage as f on f.nomeFeed = x.nomeFeed and f.pubDate = x.maxdate]
at org.hibernate.hql.internal.ast.QuerySyntaxException.convert(QuerySyntaxException.java:91)
    at org.hibernate.hql.internal.ast.ErrorCounter.throwQueryException(ErrorCounter.java:109)
    at org.hibernate.hql.internal.ast.QueryTranslatorImpl.parse(QueryTranslatorImpl.java:304)
    at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:203)
    at org.hibernate.hql.internal.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:158)
    at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:126)
    at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:88)
    at org.hibernate.engine.query.spi.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:190)
    at org.hibernate.internal.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:301)
    at org.hibernate.internal.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:236)
    at org.hibernate.internal.SessionImpl.createQuery(SessionImpl.java:1796)...........

我认为问题是Hibernate无法翻译查询，因为如果我直接运行到MySQL，这是有效的。或者，我尝试运行后续查询：

String hql = "from (select nomeFeed, title, max(pubDate) as maxdate "
                                    + "from FeedMessage "
                                    + "group by nomeFeed) as x,  FeedMessage as f "
                    + "where f.nomeFeed = x.nomeFeed and f.pubDate = x.maxdate";

但我得到的结果相同。

Answer 1

不幸的是你不能在HQL中这样做。根据hibernate文档https://docs.jboss.org/hibernate/orm/3.3/reference/en/html/queryhql.html#queryhql-subqueries

请注意，HQL子查询只能在select或where中出现条款。

而您的子查询位于 from 子句中。如果您希望在from语句中使用子查询，则必须使用本文所述的本机SQL：https://docs.jboss.org/hibernate/orm/3.3/reference/en/html/querysql.html

Hibernate：org.hibernate.hql.internal.ast.QuerySyntaxException：意外令牌:(靠近第1行，第6列......）

1 个答案: