我有一个名为definitions
的准引号数组,我想将它引入准引号tree
。我该怎么做呢?
private def generateDaoComponent(files: Array[File]) = {
val file = createNewFile(compDirectory)
val definitions = files.map(f => {
val daoName = f.getName.replace(".java", "")
val daoType = TypeName(daoName)
val daoTerm = TermName(daoName)
q"""def $daoTerm = getValueOrInstantiate($daoName, () => new $daoType(configuration))
"""
})
val tree = q"""
package database.dao {
import org.jooq.SQLDialect
import org.jooq.impl.DefaultConfiguration
import utility.StrongHashMap
trait $componentType extends StrongHashMap[String, Dao] {
this: DaoManager =>
private lazy val configuration = new DefaultConfiguration().set(connection).set(SQLDialect.POSTGRES_9_4)
${definitions.foreach(f => q"${f}")}
}
}"""
writeToFile(file, tree)
}
答案 0 :(得分:1)
这是一些疯狂的深夜编码,但我发现它归功于这个网站
3 approaches to Scala code generation
我注意到它将$params
数组传递给准引号时,它在类构造函数前面使用了两个..
,如下所示:
val params = schema.fields.map { field =>
val fieldName = newTermName(field.name)
val fieldType = newTypeName(field.valueType.fullName)
q"val $fieldName: $fieldType"
}
val json = TypeSchema.toJson(schema)
// rewrite the class definition
c.Expr(
q"""
case class $className(..$params) {
def schema = ${json}
}
"""
)
我在问题中发布的代码有两个步骤可以使其正常工作。
1)将$definitions.toList
转换为列表
2)在前面添加两个..
所以最终的代码如下:
val definitions = files.map(f => {
val daoName = f.getName.replace(".java", "")
val daoType = TypeName(daoName)
val daoTerm = TermName(new StringBuilder("get").append(daoName).toString())
q"""def $daoTerm = getValueOrInstantiate($daoName, () => new $daoType(configuration))"""
}).toList <--- HERE!
val tree = q"""
package database.dao {
import org.jooq.SQLDialect
import org.jooq.impl.DefaultConfiguration
import utility.StrongHashMap
trait $componentType extends StrongHashMap[String, Dao] {
this: DaoManager =>
private lazy val configuration = new DefaultConfiguration().set(connection).set(SQLDialect.POSTGRES_9_4)
..$definitions <-- AND HERE!
}
}"""