Question

我是如何尝试为以下输入构建哈希

[["Company", "Add"], ["Company", "Edit"], ["Company", "Delete"], ["Company", "List"], ["Caterer", "Add"], ["Caterer", "Edit"], ["User", "Add"]]

输出应为

[{'Company'=>['Add', 'List', 'Edit', 'Delete']},
 {'Caterer'=>['Add', 'List', 'Edit', 'Delete']},
 {'User'=>['Add']}]

尝试1：

input = [["Company", "Add"], ["Company", "Edit"], ["Company", "Delete"], ["Company", "List"], ["Caterer", "Add"], ["Caterer", "Edit"], ["User", "Add"]]
a=[]
input.each do |inp|
  tmp = Hash.new
  a<< tmp.update(inp[0] => inp[1])
end

结果：

[{"Company"=>"Add"}, {"Company"=>"Edit"}, {"Company"=>"Delete"}, {"Company"=>"List"}, {"Caterer"=>"Add"}, {"Caterer"=>"Edit"}, {"User"=>"Add"}]

Answer 1

input = [["Company", "Add"], ["Company", "Edit"], ["Company", "Delete"], ["Company", "List"], ["Caterer", "Add"], ["Caterer", "Edit"], ["User", "Add"]]

as_hash = input.group_by(&:first)
as_hash.each do |entity, actions|
  as_hash[entity] = actions.flatten.reject do |action|
    action == entity
  end.sort_by { |action| ['Add', 'List', 'Edit', 'Delete'].index action }
end

编辑：我刚看到你想要一对数组，而不是哈希。你可以通过以下方式做到：

as_hash.map { |pair| Hash[*pair] }

Answer 2

这应该有效

result={}
[["Company", "Create"], ["Company", "Edit"], ["Company", "Delete"], ["Company", "List"], ["Caterer", "Create"], ["Caterer", "Edit"], ["User", "Add"]].each do  |value|
   result[value[0]]=[] unless result.has_key? value[0]
   result[value[0]] << value[1]
end
puts result.to_s

{"Company"=>["Create", "Edit", "Delete", "List"], "Caterer"=>["Create", "Edit"], "User"=>["Add"]}

但不是哈希数组

如果您仍想获得阵列，可以执行此操作

r=result.map{|k,v| {k=>v} }

在ruby中使用多个数组值的哈希

2 个答案: