Question

import java.util.*;
import java.lang.*;
import java.io.*;

class Ideone
{
    public static void main (String[] args) throws java.lang.Exception
    {
        int w, a;
        double withdrawal;
        double amount;
        double left;

        Scanner in = new Scanner(System.in);

        w = in.nextInt();
        amount = in.nextDouble();
        withdrawal = (double)w;
        left=amount-withdrawal-0.50;

        if(withdrawal+0.50>amount){System.out.println("%.2f",amount);}
        else if(withdrawal%5!=0){System.out.println("%.2f",amount);}
        else{System.out.println("%.2f",left);}
    }
}

我读了接受的答案here，但它给出了错误： Ideone.java:21: error: no suitable method found for println(String,double) if(withdrawal+0.50>amount){System.out.println("%.2f",amount);}

所以我想知道我的实现有什么问题，以及正确的方法是什么。感谢。

Answer 1

为什么不使用

 system.out.print("%.2f");
 system.out.println(amount);

据我所知，

println()不能接受2个论点

使用System.out.println打印双变量

1 个答案: