Question

今天早上开始使用python编程，想要制作一个简单的应用程序，当我到处播放一首歌时，它会嗅探我手机的蓝牙。此应用程序每27秒继续搜索我的蓝牙。如果我还在，它会继续播放，但我离开或关闭我的蓝牙，我希望它停止歌曲。我有以下代码，一切正常但我得到一个错误，如果没有检测到蓝牙设备停止执行，当我离开或关闭我的设备，歌曲继续播放。请帮忙。

import socket
import mmap
from bluetooth import *
import msvcrt
import bluetooth
import pygame, time

from pygame.locals import *

pygame.mixer.pre_init(44100, 16, 2, 4096) #frequency, size, channels, buffersize
pygame.init() #turn all of pygame on.
DISPLAYSURF = pygame.display.set_mode((500, 400))
soundObj = pygame.mixer.Sound('sleep.wav')

target_name = "Joelk"
target_address = None

loop = False
isHome = False
playing = False

print("Press Esc to end....")
while loop == False:
    print("Perfoming Enquire")

    if msvcrt.kbhit():
        if ord(msvcrt.getch()) == 27:
            break
   nearby_devices = discover_devices(lookup_names = True)
print ("found %d devices" % len(nearby_devices))

if 0 == len(nearby_devices):
    print("There is no device nearby")
else:
    print("There is a device")
    for name, addr in nearby_devices:
        print (" %s - %s" % (addr, name))
        if "Joelk" == addr:
            isHome = True

    if(isHome == True):
        if(playing == True):
            print("Playing")
        else:
            soundObj.play()
            playing = True
    else:
        isHome = False
        soundObj.stop()
        print("Not Playing")

Answer 1

您从未在主循环中将is_home设置为False。对False的唯一分配发生在else分支中，只有当is_home False为break时才会执行，因此此语句无效。

如果未检测到合适的蓝牙设备，则必须设置为false。这可以通过else的帮助和for循环检测设备上的bool子句来完成。

没有所有不必要的导入，没有星号导入，没有不必要的名称，没有不必要的括号和与import pygame from bluetooth import discover_devices def main(): pygame.mixer.pre_init(44100, 16, 2, 4096) pygame.init() _display = pygame.display.set_mode((500, 400)) sound = pygame.mixer.Sound('sleep.wav') is_home = False print('Press Esc to end....') while True: print('Performing Enquire') for event in pygame.event.get(): if event.type == pygame.KEYUP and event.key == pygame.K_ESCAPE: break nearby_devices = discover_devices(lookup_names=True) print('found {0} devices'.format(len(nearby_devices))) if nearby_devices: for address, name in nearby_devices: print(' {0} - {1}'.format(address, name)) if name == 'Joelk': is_home = True break else: is_home = False if is_home: if sound.get_num_channels() > 0: print('Playing') else: sound.play() else: sound.stop() print('Not Playing') if __name__ == '__main__': main()文字的比较，并且未经测试：

playing

Sound标志已被play()对象查询当前正在播放的频道数。如果您在无间隙循环中演奏声音，您应该查看有关循环声音的int i1,i2; ....方法的可选参数。

检测到蓝牙设备时如何播放声音

1 个答案: