Question

我有一个SQL查询，其中包含一个在数据库中正确运行的函数。在我的应用程序中，我正在使用HQL和JPA实体类，此函数现在给我一个错误。我已经将其他sql查询转换为hql了，只是这个函数给了我一个问题。有人可以让我了解我需要做出哪些改变才能使这个HQL查询/功能有效吗？

错误

java.lang.IllegalStateException：没有节点的数据类型：org.hibernate.hql.internal.ast.tree.MethodNode - [METHOD_CALL] MethodNode：'（' + - [METHOD_NAME] IdentNode：'contact_info.f_user_details'{originalText = contact_info.f_user_details} - [EXPR_LIST] SqlNode：'exprList' + - [QUOTED_STRING] LiteralNode：''ContactInfo'' + - [QUOTED_STRING] LiteralNode：''UserDetails'' + - [DOT] DotNode：'contactinf1_.USER_ID'{propertyName = userId，dereferenceType = ALL，propertyPath = id.userId，path = c.id.userId，tableAlias = contactinf1_，className = database.tables.ContactInfo，classAlias = c } | + - [DOT] DotNode：'contactinf1_.USER_ID'{propertyName = userId，dereferenceType = 2，propertyPath = id.userId，path = c.id.userId，tableAlias = contactinf1_，className = database.tables.ContactInfo，classAlias = c } | - [IDENT] IdentNode：'userId'{originalText = userId} - [NUM_INT] LiteralNode：'0'

HQL

select p.firstName, p.lastName, 
contact_info.f_user_details('CONTACT_INFO','CONTACT_INFO.UserDetails',c.id.userId, 0) as details"                   
                from Personnel p, 
                ContactInfo c, UserDetails ud            
                where p.userId = c.id.userId 
                and ud.userId = p.userId;

SQL

 Select p.FIRST_NM, p.LAST_NAME,
 contact_info.F_USER_DETAILS('CONTACT_INFO','CONTACT_INFO.USER_DETAILS',ud.USER_ID,0) as USER_DETAILS
      from PERSONNEL p 
      inner Join CONTACT_INFO c
      On p.USER_ID = c.USER_ID
      inner join USER_DETAILS ud
      on ud.USER_ID = p.USER_ID

如何通过JPA将SQL函数转换为HQL函数？

0 个答案: