Question

基本上，如果在另一个符合某些条件的表中有记录，我尝试使用查询构建器从表中选择所有内容。目前我有下面的代码，但是在100K行的表格上它的速度非常慢。

 $result=  [];

    $customers = (array)DB::table('customers')->where('lastName','LIKE', Input::get('letter').'%')->orderBy('lastName','ASC')->get();

    foreach($customers as $k => $v)
    {
        if(DB::table('orders')->where('disabled','=','')->where('customerId','=',$v->id)->where('status','!=',0)->count() > 0)
        {
            array_push($result, $v);
        }
    }

任何建议都将不胜感激！此刻，这个时间在5分钟后消失。

Answer 1

目前，您正在运行一个查询来获取客户，然后查询每个客户以获取相关订单。如果您有许多客户，则会导致需要执行大量查询。

您可以通过加入这两个表来执行单个查询。

这样可以解决问题：

//get all customers
$results = DB::table('customers')
  //filter customers by lastName
  ->where('customers.lastName','LIKE', Input::get('letter').'%')
  //take only customers that have orders matching criteria below
  ->join('orders', function($query) {
    //link customer to their orders
    $join->on('orders.customerId', '=', 'customers.id');
    //consider only enabled orders
    $join->where('orders.disabled','=','');
    //consider only orders where status != 0
    $join->where('orders.status','!=',0);
  })
  //if customer has multiple orders matching criteria 
  //they will be returned multiple time, so you need to group by
  //customers.id to get only one row per customer
  ->groupBy('customers.id')
  //order by customers last name
  ->orderBy('customers.lastName','ASC')
  ->get();

Answer 2

你可以尝试这样的事情

$data = Customer::with('Order') -> where('lastName','like',$name) -> whereExists(function($query){
$query->select(DB::raw(1)) -> from('orders')
 ->whereRaw('orders.customer_id= customer.id')
 ->where('disabled','=','')
 ->where('status','!=',0);
})-> orderBy('lastname','ASC')  -> get() ->toArray();

Laravel查询构建器 - 选择其他表的ID为

2 个答案: