Question

我想要一个程序，它接受字符串作为输入，而不是从漫画[k]中搜索特定单词，并在漫画[k] []处打印字符串。这是代码

Scanner s=new Scanner(System.in);
        String str;
        int k=0;
        String[][] cartoons = {
            { "Flintstones", "Fred is a bad boy."},
            { "Rubbles", "Barney rocks."},
            { "Jetsons", "George was president of America."},
            { "Scooby Doo Gang", "Scooby Doo where are you?"} };
                boolean found=false;

        for (int i = 0; i < cartoons.length; i++) {
          System.out.print(cartoons[i][0] + ": ");
          for (int j = 1; j < cartoons[i].length; j++) {
            System.out.print(cartoons[i][j] + " ");
          }
          System.out.println();
        }
        System.out.println("Enter name to search.");
        str=s.nextLine();
             while(k<cartoons.length){
            if(str.equals(cartoons[k])){
            System.out.print(cartoons[k]);  
                found=true;
            }
            k++;
        }
    System.out.println("Not found");
        }

Answer 1

分别使用cartoons[k][0]和cartoons[k][1]。 String的数组不是String。将数组作为参数，String::equals将始终为false。我还修复了下面的循环退出条件：

Scanner s=new Scanner(System.in);
String str;
int k=0;
String[][] cartoons = {
        { "Flintstones", "Fred is a bad boy."},
        { "Rubbles", "Barney rocks."},
        { "Jetsons", "George was president of America."},
        { "Scooby Doo Gang", "Scooby Doo where are you?"} };
boolean found=false;

for (int i = 0; i < cartoons.length; i++) {
    System.out.print(cartoons[i][0] + ": ");
    for (int j = 1; j < cartoons[i].length; j++) {
        System.out.print(cartoons[i][j] + " ");
    }
    System.out.println();
}
System.out.println("Enter name to search.");
str=s.nextLine();
while(!found && k<cartoons.length){
    if(str.equals(cartoons[k][0])){
        System.out.print(cartoons[k][1]);
        found=true;
    }
    k++;
}
if (!found) {
    System.out.println("Not found");
}

搜索关键词并打印其旁边的整个句子的程序

1 个答案: