Question

我对此感到困惑。这是我的应用代码。

public void getUserInform(final String username,final String pwd) {
        new AsyncTask<Void, Void, String>() {

            @Override
            protected String doInBackground(Void... params) {
                String result = "";
                SoapObject rpc = new SoapObject(Config.SERVICEURL,
                        Config.METHODNAME);

                PropertyInfo p1 = new PropertyInfo();
                p1.setName("UserName".toString());
                p1.setValue("5100614".toString());
                p1.setType(String.class);

                PropertyInfo p2 = new PropertyInfo();
                p2.setName("pwd".toString());
                p2.setValue("E10ADC3949BA59ABBE56E057F20F883E".toString());
                p2.setType(String.class);



                rpc.addProperty(p1);
                rpc.addProperty(p2);

                System.out.println(rpc);
                System.out.println(rpc.getProperty(0).toString());
                System.out.println(rpc.getProperty(1).toString());

                SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
                        SoapEnvelope.VER11);
                envelope.dotNet = true;
                envelope.setOutputSoapObject(rpc);
                HttpTransportSE transport = new HttpTransportSE(Config.ENDPOINT);
                try {
                    transport.call(Config.SOAPACTION, envelope);
                    SoapObject objects = (SoapObject) envelope.bodyIn;
                    System.out.println(objects);
                    result = objects.getProperty(0).toString();
                } catch (IOException e) {
                    e.printStackTrace();
                } catch (XmlPullParserException e) {
                    e.printStackTrace();
                }
                System.out.println(result);
                return result;
            }

此系统输出正确

GetUser{UserName=5100614; pwd=E10ADC3949BA59ABBE56E057F20F883E; }
5100614
E10ADC3949BA59ABBE56E057F20F883E
GetUserResponse{GetUserResult=ID or Password could not be null; }

但我发现我的webservice一直认为传递的参数是空的我的网络服务在没有应用访问权限的情况下运行良好。

  [WebMethod]
        public string GetUser(string UserName,string pwd)
        {
            StreamWriter sw = File.AppendText("D:\\WebServiceLog.txt");
            string w = UserName+"///"+pwd;
            sw.Write(w);
            sw.Close();
            string result = "Unknown result!";
            if (UserName == null || pwd == null)
            {
                result = "ID or Password could not null";
            }
            else
            {
                UserService Uservcie = new UserService();
                List<UserModel> userList = Uservcie.GetUserAsList(UserName, pwd);

                if (userList.Count == 0)
                {
                    result = "can not find user";
                }
                if (userList.Count > 1)
                {
                    result = "Sorry,Not union user";
                }
                if (userList.Count == 1)
                {
                    result = userList[0].UserName.ToString() + '/' + userList[0].Name.ToString() + '/' + userList[0].Unit.ToString();
                }
            }
            return result;
        }

我不确定我的代码有什么问题。我只想使用soapobject访问带有属性的webservice。

Answer 1

rpc.addProperty("a", "myprop");

试试这个。

soapobject如何传递属性？

1 个答案: