嘿我正在尝试将toolbarMenuButton添加到我的工具栏中但由于某种原因我收到此错误
try {
Connection con = null;
ResultSet rs;
con=DB.getConnection();
// this fire returns as an Integer 4
PreparedStatement ps =con.prepareStatement("SELECT EXTRACT
(EPOCH FROM(last_reply-created_on)/60):: integer as fire from streams where id=65");
rs= ps.executeQuery();
while (rs.next()) {
// I then put this method through
System.err.println(difference(rs.getInt("fire")));
}
con.close();
return ok();
} catch (Exception e) {
System.err.println(e.getMessage());
}
private static String difference(Integer i) {
String id="";
if(i<60)
{
4 is obviously less than 60 but it is not working
id= i+ " min";
}
if(i>=60 && i<1440)
{
id=i+ " hrs";
}
if(i>=1441 && i<10080)
{
id=i+" days";
}
else
{
id=i+" weeks";
}
// returns as 4 date
return id;
}
工具栏将混合使用toolbarButton和toolbarMenuButton。现在它只是toolbarButton。
goog.ui.ToolbarMenuButton is not a function ;
最初我有selectBtn1作为ToolbarButton,它工作正常。但是当我将其转换为toolbarMenuButton(见于selectBtn2)时,它会产生上述错误。为什么? 根据文档,它们都采用相同的参数。